Example 3.18A low carbon steel bar of 147 mm diameter with length of 630 mm is beingturned with uncoated carbide insert. The observed tool life are 24 and 12 for cutting velocities of90 m/min and 120 m/min respectively. The feed and depth of cut are 0.2 mm./rev and 2 mm respectively.Use the unmachined to calculate the cutting velocity(i) When tool life is 20 min. the cutting velocity in m/min is(a) 87(b) 97(c) 107(d) 114(ii) Neglect over travel or approach of the tool. When tool life is 20 min, the machining time inremain for a single pass is(a) 5(b) 10(c) 15(d) 20

Given data as per the question A low carbon steel bar of 147 mm diameter with a length of 630 mm

Answered: Example 3.18 A low carbon steel bar of…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Write down the steps required to proof the mathematical relation for SHEAR PLANE ANGLE in Orthogonal Cutting Model. i-e. Prove the following relation:
In orthogonal turning of a low carbon steel bar of diameter 150 mm with uncoated carbide tool. the cutting velocity is 90 m/min The feed is 0.24 mm/rev and the depth of cut is 2 mm. The chip thickness obtained is 0.48 mm If the orthogonal rake angle is zero and the principal cutting edge angle is 90° Calculate the shear angle in degree.
Find the time required for one full cut on a work piece of 350mm long and 20 mm in diameter. The cutting speed is 30 meters per minute and the feed is 0.5mm per revolution. Average. SHOW YOUR SOLUTION WITH DRAWINGS
In orthogonal turning of low carbon steel pipe with principal cutting edge angle of 90°, the main cutting force is 1000 N and the feed force is 800 N. The shear angle is 25° and orthogonal rake angle is zero Employing Merchant's theory, what is the ratio of friction force to normal force acting on the cutting tool?
In orthogonal turning of a bar 100 mm diameter with a feed of 0.25 mm/rev., depth of cut = 4 mm, cutting velocity = 90 m/min. it is observed that the main cutting force is perpendicular to friction force acting at the chip tool interface and cutting force is 1500 N. find (i) rake angle (ii) normal force.
Find the machining time required to turn a mild steel rod from 65mm to 58 mm over a length of 100 mm by using a carbide insert. If the approach length and over run length is taken as 5 mm, Cutting speed as 20 m/min and feed is =0.2 mm/rev, and the depth of cut is 0.5mm
Assuming that the coefficient of friction is 0.25, calculate the maximum depth of cut forturning a hard aluminium alloy on a 15-kW lathe (with a mechanical efficieny of 80%) at awidth of cut of 6 mm, rake angle of 0˚, and a cutting speed of 90 m/min, shear strength of 150 MPa.
2 1.46 Explain why the power requirements in cutting depend on the cutting force but not the thrust force.
A student is using a lathe with 80-hp and 80% efficiency to fabricate a copper alloy with Sy= 1200 ksi. If the width of cut is 0.30 in. and the student set a rake angle of 0° and a cutting speed of 200 ft/ min while she assumed a coefficient of friction to be 0.5. What is the maximum depth of cut the student can achieve?
A student is using a lathe with 80-hp and 80% efficiency to fabricate a copper alloy with Sy = 1200ksi If the width of cut is 0.30 inand the student set a rake angle of 0and a cutting speed of 200fl / min while she assumed a coefficient of friction to be 0.5. What is the maximum depth of cut the student can achieve?
A steel rod 250 mm long and 200 mm in diameter is being reduced to 190 mm in diameter all over its length in one travel. The machine spindle rotates at 500 rpm, whereas the tool is moving at an axial feed of 0.5 mm/rev; calculate the following: Material removal rate (mm3/min) Consumed gross power in Nm/s if cutting force is 477.5N and mechanical efficiency is 90% Cutting time plzz complete in 30 minutes
A motorised metal guillotine machine is required to cut 45 mm diameter hole in a plate of 20 mm thickness at rate of 35 holes per minute. It requires a torque of 7 Nm for an area of hole in mm2. If the cutting takes 1/10 of a second and the speed of its flywheel varies from 165 rpm to 145 rpm, calculate:

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