Example: A 50 kVA distribution transformer has iron loss of 600W and full-load copper loss of 700W. the transformer is supplying load. The load cycle is as under: 35kW and 0.8 power factor lag for 6 hours; 30kW and 0.707 lag for 8 hours and no- load for 10 hours. Calculate the all-day efficiency of the transformer.

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Example: A 50 kVA distribution transformer has iron loss of 600W and full-load
copper loss of 700W. the transformer is supplying load. The load cycle is as under:
35kW and 0.8 power factor lag for 6 hours; 30KW and 0.707 lag for 8 hours and no-
load for 10 hours. Calculate the all-day efficiency of the transformer.
Page 1 ot 1
56 words E Arabic raq
区 You
6:41 PM
P Type here to search
105°F Sunny ^
a 40) E
6/19/2021
Transcribed Image Text:qu Word Sign in File Home Insert Draw Design Layout References Mailings Review View Help O Tell me what you want to do A Share X Cut a Copy P Find- Times New Roma -14 - A A Aa - =-E- T cDdEe cDdEe :DdEe CcDdEe dEe CeDdEe 1 Normal TNo Spac. Heäding 1 Heading 2 ab Replace D Select- Paste BIU- abc x, x A aly- A- ==== E- Title Subtitle Format Painter Clipboard Font Paragraph Styles Editing Example: A 50 kVA distribution transformer has iron loss of 600W and full-load copper loss of 700W. the transformer is supplying load. The load cycle is as under: 35kW and 0.8 power factor lag for 6 hours; 30KW and 0.707 lag for 8 hours and no- load for 10 hours. Calculate the all-day efficiency of the transformer. Page 1 ot 1 56 words E Arabic raq 区 You 6:41 PM P Type here to search 105°F Sunny ^ a 40) E 6/19/2021
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