Example : A concrete mix required for construction of an industrial building. Cement is PKC32.5. Specific gravity of cement is 31.5 kg/dm. Vibrator will be used during the placement of concrete. The grading analysis of bulk aggregate as follows. Specific gravity and bulk density of aggregates as follows: Sand 2.60 kg/dm3 1.30 kg/dm3 Coarse Aggregate 2.65 kg/dm 1.70 kg/dm3 Pebble 2.72 kg/dm3 1.55 kg/dm Target strength has been desired as 20 + 5 = 25 MPa Assume, Workability of the resulting concrete will be Plastic. Minimum amount cement will be 350 kg/m Grading of the bulk aggregate Sieve size (mm) 16 8 0.5 0.25 Cumulative 100 64.8 48.7 32.8 24.0 12.0 4.5 Passing (%)

Example : A concrete mix required for construction of an industrial building. Cement is PKC32.5. Specific gravity of cement is 31.5 kg/dm. Vibrator will be used during the placement of concrete. The grading analysis of bulk aggregate as follows. Specific gravity and bulk density of aggregates as follows: Sand 2.60 kg/dm3 1.30 kg/dm3 Coarse Aggregate 2.65 kg/dm 1.70 kg/dm3 Pebble 2.72 kg/dm3 1.55 kg/dm Target strength has been desired as 20 + 5 = 25 MPa Assume, Workability of the resulting concrete will be Plastic. Minimum amount cement will be 350 kg/m Grading of the bulk aggregate Sieve size (mm) 16 8 0.5 0.25 Cumulative 100 64.8 48.7 32.8 24.0 12.0 4.5 Passing (%)

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter2: Soil Deposits-origin, Grain-size, And Shape

Section: Chapter Questions

Problem 2.15CTP: In concrete work, Fuller and Thompson (1907) suggested that a dense packing of grains can be...

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Compute for the concrete mix proportion for a 6" diameter concrete cylinder mold with 12" height and 6"x6"x21" concrete beam mold Slump = 25mm to 50mm fc' = 3000psi at 28 days Maximum size of Coarse Aggregates (gravel) = 3/4" Unit weight of Coarse aggregate= 1651 kg/m³ Cement Type I Specific Gravity=3.15 Specific Gravity for Coarse Aggregates=2.77 Specific Gravity for Fine Aggregate=2.61 Fineness Modulus (FM)=2.69 Interpolate values that are not present/exact in each table hint: compute for the mix proportion of 1cubic meter of concrete after getting the mix proportions relate it to the volume of the structure above (concrete cylinder and concrete beam) to get the batch weights of the materials.
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket =14L Weight of empty bucket = 9.21kg Weight of bucket filled with dry rodded coarse aggregate: Trial 1 =34,75 kg Trial 2 =34.06 kg Trial 3 =35.74 kg a. Calculate the average dry-rodded unit weight b.If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids between aggregate particles for each trial.
Strength requirements, in MPa – 30.68 Mpa Water cement ratio, in decimal – 0.45 Coarse aggregate requirements (dry), in kg/m3 – 992.kg/m3 Air content, in percent – 3.5% Water content, kg/m3 – 184 kg/m3 Cement, in kg/m3 – 408.89 kg/m3 Determine the Admixtures in ml/m3 Fine aggregate requirements (dry), in kg/m3 Net Water Content, in kg/m3
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained:Volume of bucket = 12 ft3Weight of empty bucket = 20.3 lbWeight of bucket filled with dry rodded coarse aggregate:Trial 1 = 76.6 lbTrial 2 = 75.1 lb Trial 3 = 78.8 lba. Calculate the average dry-rodded unit weightb. If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids between aggregate particles for each trial.
A concrete mix has a ratio os 1:2:4 by mass. The properties of thematerials to be used are tabulated below.MATERIALS. SPECIFIC GRAVITYCEMENT 3.33SAND 2.65GRAVEL 2.67Cement weighs 40 kg per bag. Use 24 liters of water per bag of cement Compute the volume of cement solids per bag of cement in cu m.Compute for the required volume of sand solids per bag of cement.Compute for the volume of concrete that can be produced per bag of cement 0.1
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained:Volume of bucket = 14 LWeight of empty bucket = 9.21 kgWeight of bucket filled with dry rodded coarse aggregate:Trial 1 = 34.75 kgTrial 2 = 34.06 kg Trial 3 = 35.74 kga. Calculate the average dry-rodded unit weightb. If the bulk dry specific gravity of the aggregate is 2.620, calculate thepercent voids between aggregate particles for each trial.
determine the effective specific gravity of aggregates. DATA: Specific Gravity: Fine Agg = 2.603 Coarse Agg = 2.740 Asphalt Cement = 1.048 Percent By Weight: Fine Agg = 47.90 Coarse Agg= 47.78 Asphalt Cement= 100-FA-CA
choose true or false If you know that weights of coarse aggregate as follow :Weight of aggregate stock = 5350 gm, weight of aggregate in oven dry= 5200 gm, weight of aggregate submerged in water =3254 gm, weight of aggregate SSD= 5220 gm , According to weights above , the oven dry bulk specific gravity is 2.325
Situation 2. Given the following data for a concrete mix:Target Concrete Strength = 40 MPaSlump = 75 mm to 150 mmWater – Cement Ratio = 0.48Unit Weight of Concrete = 23.4 KN/m 3Water Content = 180 Kg/m 3Entrapped Air = 1%Fine Aggregate = 33% of the total volume of the aggregatesSpecific Gravity of Materials:Cement = 3.15Fine Aggregate = 2.68Coarse Aggregate = 2.64 4. Calculate the required weight (kg) of cement and water per cubic meter of concrete. A. 530 C. 632 B. 587 D. 555 5. Calculate the required weight (kg) of fine aggregates per cubic meter of concrete. A. 611 C. 562 B. 745 D. 452 6. Calculate the required weight (kg) of coarse aggregates per cubic meter of concrete. A. 1222 C. 904 B. 1124 D. 1490
Determine Admixtures in ml/m3 Fine aggregate requirements (dry), in kg/m3 Net Water Content, in kg/m3
Calculate the bulk specific gravity of combined aggregate if you know the specific gravities of coarse aggregate (C), fine aggregate (F) and Mineral Filler (MF) are 2.61, 2.63 and 2.71 respectively. The percent for C, F, and MF can be determined based on the gradation shown below
3. Coarse aggregate is placed in a rigid bucket and compacted with a tamping rod to determineits unit weight. The following data are obtained:• Volume of bucket = 0.5 ft3• Weight of empty bucket = 20.3 lb• Weight of bucket filled with dry compacted coarse aggregate = 76.8 lba) Calculate the dry-compacted unit weight of the aggregate.b) If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids.