Explain your answer. Below is a pedigree showing the inheritance of colorblindness in Akoto family. Colorblindness is a recessive and X-linked trait (x®). The allele for normal vision is dominant and is represented by X°. 1 2 3 5 5 6 IV 2 1. What are the genotypes of the founding parents (I-1, l-2)? 2. What is the percentage of the affected offspring (II)? 3. What is the phenotype of Il-2? 4. Is the inheritance autosomal or sex-linked? 2.
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- I. Perform the indicated single-gene and two-gene crosses. Show all work. Show all Punnett squares. List the gene or genes involved, list and define all allele symbols, and indicate the genotypes of the individuals you are crossing above the Punnett square. Answer questions that ask for a ratio as a ratio and questions that ask for a percent as a percent. One form of red-green color blindness is an X-linked recessive trait. A heterozygote woman has children with a normal man. What is the percentage chance that they will have a child with color blindness?Complete the sentences You cross two mice with wildtype (long) tails and collect a male offspring with a short tail, who you name Squeak. Tail length is controlled by the gene Lf, which is a paternally imprinted gene in mice. Given that this is an imprinted gene, explain the inheritance and expression of the trait. 1. Squeak’s short tail allele was inherited from the _____ (female, male, or either) parent. That parent did not express the trait because the allele was ____ (unmethylated, methylated) in the parent’s somatic cells and was inherited from that parent’s own ___ (mother, father, either mother or father)2. If Squeak’s offspring inherit the short tail allele from Squeak, will they have short tails? Yes or No?3. If Squeak was a female instead of a male, which answers in this question would change? ____ (some of the answers, all of the answers, or only the one about the offspring)Hemophilia is a X-linked genetic disorder causing blood clotting problem. A dominant allele on the X chromosome, H, results in normal blood clotting, but a recessive allele for this gene, h, prevents normal clotting. Julie has hemophilia. Her husband, Brian, does not. What is the probability that Julie and Brian have a child that suffers from hemophilia? In your answer: - Show both lizards’ genotypes; - The complete Punnett square; - Answer the question.
- Punnet square problems A=Codominant; B=Codominant; O=Recessive Mary is homozygous for type A blood. Steve is homozygous for type O blood. If they have children, what are the possible phenotypes and genotypes of their children, and what is the probability of each? Mary and Steve have a son, Brad. Brad’s wife, Samantha is heterozygous for type B blood. If they have children, what are the possible phenotypes and genotypes of their children, and what is the probability of each? Stella loves roses and decides to cross her red rose with her white rose. All of the resulting offspring of this cross are pink roses. What can you say about the red and white alleles as a result of this cross? Stella decides to cross two of the pink roses. What are the possible genotypes and phenotypes of the offspring and the probabilities of each? DNA replication, Transcription and Translation problems It is S phase of the cell cycle, and time to replicate the cell’s DNA. Using the following strand of DNA…Help me create a pedigree of this information: Pedigree analysis: Generation 1: Normal parents (AA x AA) Generation 2: Carrier parents (AA x AS) Generation 3: Affected child (AS x AS) Generation 4: Affected grandchild (SS) This pedigree has two normal parents in the first generation. Second generation carriers carry the sickle cell trait from one parent. The disease is 25% more likely to be inherited in the third generation if both parents have the 'S' allele. If both parents have the 'S' allele, their children will have sickle cell anemia in the fourth generationI. Perform the indicated single-gene and two-gene crosses. Show all work. Show all Punnett squares. List the gene or genes involved, list and define all allele symbols, and indicate the genotypes of the individuals you are crossing above the Punnett square. Answer questions that ask for a ratio as a ratio and questions that ask for a percent as a percent. In humans, albinism is a recessively determined trait. One form of hereditary deafness is also a recessive trait. Show the cross of a man who is heterozygous for skin pigmentation and heterozygous for hereditary deafness with a woman who is albino and deaf. Show the expected phenotype ratio of the offspring.
- 1. Hemophilia is due to a sex-linked gene. It is recessive and found on the X chromosome. A woman who is a carrier for hemophilia marries a normal man. What will be the possible phenotypes of their children? Use a punnet square. 2. A phenotypically normal man, who has a hemophiliac brother, marries a normal woman, who is not a carrier. What is the probability that any of their children will be hemophiliac? Use a punnet square. 3. Color-blindness is an X-linked, recessive trait. If a normal-sighted woman, whose father was color-blind, marries a colorblind man, what is the probability that they will have a son who is color-blind? Use a punnet square. 4. A man and woman, both of normal vision, have: 1) a color-blind son (#1) who has a daughter of normal vision 2) a daughter (#1) of normal vision who has one color-blind son and one normal vision son 3) another daughter (#2) of normal vision who has five sons, all with normal vision What are the probable genotypes of the…Please write your complete solution (paper). Albinism in humans is inherited as a simple recessive trait. Determine the genotypes of the parents and their children when two normal parents have 3 normal children and 1 albino.1. What is the pattern of inheritance of 5-Alpha Reductase 2 Deficiency? answer choices: X-linked recessive X-linked dominant autosomal recessive autosomal dominant maternal/mitochondrial Y-linked 2. What is the likely genotype of individual V-8? a = recessive allele A = dominant allele What is the likely genotype of individual V-8? a = recessive allele A = dominant allele answer choices: XaY XAY aa Aa AA 3. Imagine that individual V-8 marries a female cousin who is a carrier of the 5αRD mutation. What is the probability that they will have a child who has the disorder? Enter your answer as a fraction
- Please write your complete solution (paper). Albinism in humans is inherited as a simple recessive trait. Determine the genotypes of the parents and their children when a normal male and albino female have 2 normal and 2 albino children.Analysis of X-Linked Dominant and Recessive Traits A young boy is color-blind. His one brother and five sisters are not. The boy has three maternal uncles and four maternal aunts. None of his uncles children or grandchildren is color-blind. One of the maternal aunts married a color-blind man, and half of her children, both male and female, are color-blind. The other aunts married men who have normal color vision. All their daughters have normal vision, but half of their sons are color-blind. a. Which of the boys four grandparents transmitted the gene for color blindness? b. Are any of the boys aunts or uncles color-blind? c. Is either of the boys parents color-blind?A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What if the couple wanted prenatal testing so that a normal fetus could be aborted?