Express the following numbers in scientific notation: 1. 1 230 045 600 000 2. 0.00000876000 2meinos 3. 0.00034500 X 4. 958 000.8900 × 10-6h bne
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- How many molecules are contained in 5.00 microliters of methanol (CH4O)? The density of methanol is 0.792 g/mL. Use these atomic masses: C = 12.011 amu; H = 1.008 amu; O = 15.999 amu. Input your result in scientific notation using the format with the lower case e representing the x10. For example, in this format the number 1.234x109 would be expressed as 1.234e9. The number 1.234x10-9 would be expressed as 1.234e-9 Not these answers 0.1569 1.23 0.1569 0.0001Complete the table.a. 1245 kg 1.245 * 106 g 1.245 * 109 mgb. 515 km _____dm _____cmc. 122.355 s _____ms _____ksd. 3.345 kJ _____J _____mJThree liquid substances of the same mass and have an S.G. of 1.50, 0.835 and 1.2 were being mixed to form a new compound. Estimate the resulting density. a. 1.1407g/cm3 b. 1.1121g/cm3 c. 1.1454g/cm3 d. 1.2232g/cm3
- (atk) Complete all calculations using the appropriate number of sigfigs 1) (4.184 Jg⋅∘C)(50.0 g)/(67.34 ∘C−24.56 ∘C) = ___ (J) 2) 2.385 g−1.978 g/2.385 g×100% = ___ (%) 3) e0.856(4.69 × 10−7) = ___ (M−1s−1) 4) 112.99 minutes to daysA 76.00 pound flat of mercury $156.50. The density of margarie is 13.534g/cm3. Find the price of 1cubic inch of mercury by calculating intermediate valuesWhat is the correct scientific notation for 0.00541cm? Use "E" to indicate the base (x10). Do not include any spaces in your answer. example format: 6.02E23
- 7.2 heat of reaction from bomb Aleks takes significant figures very seriously. ThanksComplete the following addition and subtraction problems in scientific notation.a. (6.23 × 1 0 6 kL) + (5.34 × 1 0 6 kL)b. (3.1 × 1 0 4 mm) + (4.87 × 1 0 5 mm)c. (7.21 × 1 0 3 mg) + (43.8 × 1 0 2 mg)d. (9.15 × 1 0 -4 cm) + (3.48 × 1 0 -4 cm)e. (4.68 × 1 0 -5 cg) + (3.5 × 1 0 -6 cg)f. (3.57 × 1 0 2 mL) - (1.43 × 1 0 2 mL)g. (9.87 × 1 0 4 g) - (6.2 × 1 0 3 g)h. (7.52 × 1 0 5 kg) - (5.43 × 1 0 5 kg)i. (6.48 × 1 0 -3 mm) - (2.81 × 1 0 -3 mm)j. (5.72 × 1 0 -4 dg) - (2.3 × 1 0 -5 dg)Please answer all questions and show calculations For the image attached For 1. a Mass of metal: Trial 1 is 35.0228 g Trial 2 is 35.0915 g Trial 3 is 34.0821 g Mass of water: Trial 1 is 20.0177 g Trial 2 is 20.0250 g Trial 3 is 20.0168 g For delta t of water: Trial 1 is 15.5 C Trial 2 is 15.7 C Trial 3 is 15.1 C For delta t of metal Trial 1 is 80.1 C Trial 2: 80.2 C Trial 3: 79.5 C For B my calculated Specific heat is: Trial 1 is 0.462 Trial 2 is 0.467 Trial 3 is 0.466
- Part A 5100000 g 5.10×106g 5.1×106g 0.510×107g 0.51×107g 5.1×10-6g Part B 26000 s 2.60×104s 2.6×10 -4s 0.260×105s 0.26×105s 2.6×104s Part C 40000 mm 4.00×104m 0.40×105m 4.0×10-4m 0.400×105m 4.0×104mExpress these non-exponentially, and choose the unit and prefix that works best: 1.9 x 10^-4 l 4 x 10^-3 s 6.5 x 10^-8 g a. 1.9 ml; 4 ms; 65 ng b. 0.19 ml; 4 ms; 65 mg c. 0.19 ml; 40 ms; 65 g d. 0.19 ml; 4 ms; 65 ng e. 0.19 ml; 4 ms; 0.65 ga. Convert 360 s to ms. e. Convert 2.45 × 1 0 2 ms to s.b. Convert 4800 g to kg. f. Convert 5 µm to km.c. Convert 5600 dm to m. g. Convert 6.800 × 1 0 3 cm to km.d. Convert 72 g to mg. h. Convert 2.5 × 1 0 1 kg to Mg.