Question
Asked Dec 13, 2019
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A object of mass 3.00 kg is subject to a force Fx that varies with position as in the figure below.

If the object has a speed of 0.400 m/s at x=0 

 find its speed at x=5.00 m 

 and its speed at x=17.0 m

 
F, (N)
4
1
x (m)
10 12 14 16 18 20
2 4 6 8
3.
2.
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F, (N) 4 1 x (m) 10 12 14 16 18 20 2 4 6 8 3. 2.

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Expert Answer

Step 1

Area under force-displacement graph will give the work done.

Area under graph from x=0 m to x=5 m is,

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W = Area (5.00m)(4N) 2 =10J

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Step 2

According to work energy theorem, work done will equal to change in kinetic energy.

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Step 3

Area under graph from x=0 m to ...

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W = Area -G5.00m)(4N) - (6m)(4N) -(6.00 m)(4N)} (Ix2)(mo0»}-(: =10J+24 J+12J =46J

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