Fe(II) can be precipitated from a slightly basic aqueous solution by bubbling oxygen through the solution, which converts Fe(II) to insoluble Fe(III):$$4Fe(OH)+(aq)+4OH−(aq)+O2​(g)+2H2​O(l)4Fe(OH)3​(s) How many grams of O2 are consumed to precipitate all of the iron in 75.0 mL of 0.0550 M Fe(II)?

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Asked Jan 14, 2020
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Fe(II) can be precipitated from a slightly basic aqueous solution by bubbling oxygen through the solution, which converts Fe(II) to insoluble Fe(III):

$$4Fe(OH)+(aq)+4OH−(aq)+O2​(g)+2H2​O(l)4Fe(OH)3​(s)



 How many grams of O2 are consumed to precipitate all of the iron in 75.0 mL of 0.0550 M Fe(II)?
    

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