Fernando is doing his pre-lab homework for Chemistry. He is asked to predict how many grams of CO2 are produced if 2.09 mol of HCl are reacted according to this balanced chemical equation shown. CaCO3 + 2HCI → CaCl2 + CO2 + H2O He performs the following calculation. 1 molEo, 2 metHCI 44.01 g CO, 1 mol-EO, 2.09 motHCT x - = 46.0 g CO, from the coefficients of the balanced equatio On the day of the lab his group obtains 43.9 grams of CO, as their experimental result. What is their percent yield? `round your answer to the tenths place, i.e. one decimal place

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter3: Chemical Reactions
Section3.2: Balancing Chemical Equations
Problem 3.1CYU: (a) Butane gas, C4H10, can burn completely in air [use O2(g) as the other reactant] to give carbon...
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Fernando is doing his pre-lab homework for Chemistry. He is asked to predict how many grams of Co, are produced if 2.09 mol of HCl are reacted according to this balanced
chemical equation shown.
CaCO3 + 2HCI - CaCl, + CO2 + H,O
He performs the following calculation.
1 molEo,
2 motHCT
44.01 g CO,
1 molEo,
2.09 motHCT x
= 46.0 g CO,
from the coefficients
of the balanced
equation
On the day of the lab his group obtains 43.9 grams of CO, as their experimental result. What is their percent yield?
`round your answer to the tenths place, i.e. one decimal place
Transcribed Image Text:Fernando is doing his pre-lab homework for Chemistry. He is asked to predict how many grams of Co, are produced if 2.09 mol of HCl are reacted according to this balanced chemical equation shown. CaCO3 + 2HCI - CaCl, + CO2 + H,O He performs the following calculation. 1 molEo, 2 motHCT 44.01 g CO, 1 molEo, 2.09 motHCT x = 46.0 g CO, from the coefficients of the balanced equation On the day of the lab his group obtains 43.9 grams of CO, as their experimental result. What is their percent yield? `round your answer to the tenths place, i.e. one decimal place
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