Ffrict= From= P=0.50 a= Fnorm (normal force) = Ffrict (force of friction) = Fgrav (force of gravity) = a (acceleration) = ---- ZF (net force) = ____________N O m = 8 kg ΣF= 30° Fgav = 81 7 ______N N ____________N m/s/s, right m/s/s, right Fhens = 60 N W

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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g= 10 m/s^2
Ffrict =
Fnown
μ=0.50
a=
Fnorm (normal force) =
Ffrict (force of friction) =
Fgrav (force of gravity) =
a (acceleration) =
ZF (net force) =
III =
ΣF=
Fyav
- 8 kg
N
N
30°
N
N
m/s/s, right
m/s/s, right
Flens- 60 N
W
Transcribed Image Text:Ffrict = Fnown μ=0.50 a= Fnorm (normal force) = Ffrict (force of friction) = Fgrav (force of gravity) = a (acceleration) = ZF (net force) = III = ΣF= Fyav - 8 kg N N 30° N N m/s/s, right m/s/s, right Flens- 60 N W
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