Figure 1(a) shows a series fed class A amplifier circuit. In order to achieve the maximum efficiency, the Q point must be located at the center of the DC load line as shown in Figure 1(b). This generates the maximum output current swing of Vcc Icmax (p – p) = RC and the maximum output voltage swing is VCEmax (p – p) = Vcc Assume that the maximum input de power is Vềc Pimax(dc) = Vcc!cQ(max)=Vcc \7' Rc. %3D %3D 2Rc Find the maximum efficiency, 7 of this circuit.

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Figure 1(a) shows a series fed class A amplifier circuit. In order to achieve the
maximum efficiency, the Q point must be located at the center of the DC load line as
shown in Figure 1(b). This generates the maximum output current swing of
Icmax (p – p)
RC
and the maximum output voltage swing is
VCEmax(p – p) = Vcc
Assume that the maximum input de power is
(1 Vcc
Pimax(dc) = Vcc!cQ(max)=Vcc \2° Rc.
2Rc
Find the maximum efficiency, 7 of this circuit.
Transcribed Image Text:Figure 1(a) shows a series fed class A amplifier circuit. In order to achieve the maximum efficiency, the Q point must be located at the center of the DC load line as shown in Figure 1(b). This generates the maximum output current swing of Icmax (p – p) RC and the maximum output voltage swing is VCEmax(p – p) = Vcc Assume that the maximum input de power is (1 Vcc Pimax(dc) = Vcc!cQ(max)=Vcc \2° Rc. 2Rc Find the maximum efficiency, 7 of this circuit.
Vcc
Load
Ic
RB
Power
transistor
V;
(a)
- Input signal
Vcc
-Rc
Output
current swing
Vcc
VCE
Output
voltage swing
(b)
Figure 1
Transcribed Image Text:Vcc Load Ic RB Power transistor V; (a) - Input signal Vcc -Rc Output current swing Vcc VCE Output voltage swing (b) Figure 1
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