Figure 3 depicts a section of printed circuit carrying a current I of (100 + 10X) mA. The incoming and outgoing conductors are long, have negligible width and are connected at their ends by a conductive bridge where d (5+X) mm. %3D ...... 45 Figure 3 Assuming the relative permeability of the substrate to be 1, calculate the magnitude and direction of the magnetic flux density at position A. Note that X is the last digit of your student number. For example, if your number is C1700123, then I = 100 + (10)(3) = 130 and d = 5+3 = 8 if your number is C1700100, then I = 100 + (10)(0) = 100 and d = 5+0 = 5 %3D %3D

College Physics
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ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
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Chapter23: Electromagnetic Induction, Ac Circuits, And Electrical Technologies
Section: Chapter Questions
Problem 27PE: Figure 23.59 A coil is moved into and out of a region of uniform magnetic field. A coil is moved...
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X=8
c) Figure 3 depicts a section of printed circuit carrying a current / of (100 +
10X) mA. The incoming and outgoing conductors are long, have negligible
width and are connected at their ends by a conductive bridge where d :
(5+ X) mm.
.....
450
d
Figure 3
Assuming the relative permeability of the substrate to be 1, calculate the
magnitude and direction of the magnetic flux density at position A.
Note that X is the last digit of your student number. For example,
if your number is C1700123, then I = 100 + (10)(3) = 130 and d = 5+3 = 8
if your number is C1700100, then I = 100 + (10)(0) = 100 and d = 5+0 = 5
%3D
%3D
Transcribed Image Text:c) Figure 3 depicts a section of printed circuit carrying a current / of (100 + 10X) mA. The incoming and outgoing conductors are long, have negligible width and are connected at their ends by a conductive bridge where d : (5+ X) mm. ..... 450 d Figure 3 Assuming the relative permeability of the substrate to be 1, calculate the magnitude and direction of the magnetic flux density at position A. Note that X is the last digit of your student number. For example, if your number is C1700123, then I = 100 + (10)(3) = 130 and d = 5+3 = 8 if your number is C1700100, then I = 100 + (10)(0) = 100 and d = 5+0 = 5 %3D %3D
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