In a Hall-effect experiment, a current of 3.0 A sent lengthwise through a conductor 1.0 cm wide, 4.0 cm long, and 10 mm thick produces a transverse (across the width) Hall potential difference of 10 mV when a magnetic field of 1.5 T is passed perpendicularly through the thickness of the conductor. From these data, find (a) the drift velocity of the charge carriers and (b) the number density of charge carriers. (c) Show on a diagram the polarity of the Hall potential difference with assumed current and magnetic field directions, assuming also that the charge carriers are electrons.

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A: Use the right hand-thumb rule to find the direction of the magnetic field.Right hand rule: Consider…

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A: Distance b/w plates, d =  2 mm = 2 x 10-3m dV/dt = 120 Volts/s

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A: The magnetic field at distance,

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Q: Q. 5: (a)The Hall effect can be used to calculate the charge-carrier number density in a di0 2i 1ed…

A: Hall coefficient is given by,                               RH = tVHIB     ----(1) where,     t -…

Q: The exchange coupling as being responsible for ferromagnetism is not the mutual magnetic interaction…

A: Given, magnetic dipole moment, μ = 2.2×10-23 JTdistance, r = 12 nm

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A: The equation for the intensity of the laser beam is given by

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A: When a charged particle enters into a magnetic field, it experiences a magnetic force equal to qvB,…

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A: Given that:B=2×10-3  Tv=107 m/s

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Q: A certain commercial mass spectrometer is used to separate uranium ions of mass 3.92 × 10-25 kg and…

A:

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A: Detailed solution of this question is given in below steps.

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A: The equation for the kinetic energy of the electron is given by,

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Q: Q. 5: (a)The Hall effect can be used to calculate the charge-carrier number density in a conductor.…

A:

Q: A strip of copper is placed in a uniform magnetic field of magnitude 2.5 T. The Hall electric field…

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Q: Consider the mass spectrometer shown schematically in the figure below. The magnitude of the…

A: Given data:      Electric field, E = 2.10×103V      Magnetic field, B = 0.0300 T      Mass, m =…

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Q: Consider the mass spectrometer shown schematically in the figure below. The magnitude of the…

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Q: A velocity selector consists of electric and magnetic fields described by the expressions E = E k…

A: Given : E = E k B = B j where B = 10 mT K.E = 840 eV

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A: Here, the magnitude of magnetic force equals the centripetal force. Thus, the equation for the…

Q: The exchange coupling as being responsible for ferromagnetism is not the mutual magnetic interaction…

A: magnetic dipole moment 1.2 x 10-23 J/T,

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A:

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Magnetic Force

A magnetic force arises when a charged particle or a current-carrying conductor is placed in a magnetic field. It is created because of the movement of the charged particles.