Figure 4 shows a small lightbulb suspended at distance di = 250 cm above the surface of the water in a swimming pool where the water depth is d2 = 200 cm. The bottom of the pool is a large mirror. How far below the mirror surface is the image of the bulb? (Hint: Assume that the rays are close to a vertical axis through the bulb, and use the small-angle approximation in which sin 0= tan 0 × 0.) di d2 Mirror Figure 4

University Physics Volume 3
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Chapter2: Geometric Optics And Image Formation
Section: Chapter Questions
Problem 118P: A point source of light is 50 cm in front of a converging lens of focal length 30 cm. A concave...
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Figure 4 shows a small lightbulb suspended at distance di = 250 cm above the surface
of the water in a swimming pool where the water depth is d2 = 200 cm. The bottom of
the pool is a large mirror. How far below the mirror surface is the image of the bulb?
(Hint: Assume that the rays are close to a vertical axis through the bulb, and use the
small-angle approximation in which sin 0= tan 0= 0.)
di
d2
Mirror
Figure 4
Transcribed Image Text:Figure 4 shows a small lightbulb suspended at distance di = 250 cm above the surface of the water in a swimming pool where the water depth is d2 = 200 cm. The bottom of the pool is a large mirror. How far below the mirror surface is the image of the bulb? (Hint: Assume that the rays are close to a vertical axis through the bulb, and use the small-angle approximation in which sin 0= tan 0= 0.) di d2 Mirror Figure 4
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