Figure 4. How to correctly measure the siba.. weight hanger carries the required added masses. M₁² (8) = 16,55 Msw (8) Table # 1: Determination of the spring constant K g= 9.80 m/s² xo (cm) = 50 100 150 200 250 MT = Mh + Msw MT (8) MT (kg) F=W=Mrg F (N) 0 xf (cm) 0.6517 1.1417 6.6.5, 0.066.5 1/6:52 0.11 6.5 166.5 0.78 6.5 1.63/7 216.2 0.2165 21217 266,55 02. 266.5 2.6117 Average force constant Kavg Force constant Ktren from the slope of the trendline in the graph % relative difference between Kavg and Ktren Mh: Mass of the weight hanger Msw: Mass of added slotted weights MT: Total Mass W: Weight of hanger plus slotted weights 1₁7 3.3 X = Xf- Xo 4.9 6.9 8 x (cm) X (m) 0 K= the F(N) x(m) K (N/m) 0.2 0.1 6/5/168 2.5ch 0.025 45.068 4on 0.09 40,7925 55 0.055 38.576 36 36 4 7.2 0.072 36.9936|||| Xo: Position of the spring's bottom (unstretched) xf Position of the spring's bottom (stretched) x: Elongation of the spring K: Force constant of the spring
Figure 4. How to correctly measure the siba.. weight hanger carries the required added masses. M₁² (8) = 16,55 Msw (8) Table # 1: Determination of the spring constant K g= 9.80 m/s² xo (cm) = 50 100 150 200 250 MT = Mh + Msw MT (8) MT (kg) F=W=Mrg F (N) 0 xf (cm) 0.6517 1.1417 6.6.5, 0.066.5 1/6:52 0.11 6.5 166.5 0.78 6.5 1.63/7 216.2 0.2165 21217 266,55 02. 266.5 2.6117 Average force constant Kavg Force constant Ktren from the slope of the trendline in the graph % relative difference between Kavg and Ktren Mh: Mass of the weight hanger Msw: Mass of added slotted weights MT: Total Mass W: Weight of hanger plus slotted weights 1₁7 3.3 X = Xf- Xo 4.9 6.9 8 x (cm) X (m) 0 K= the F(N) x(m) K (N/m) 0.2 0.1 6/5/168 2.5ch 0.025 45.068 4on 0.09 40,7925 55 0.055 38.576 36 36 4 7.2 0.072 36.9936|||| Xo: Position of the spring's bottom (unstretched) xf Position of the spring's bottom (stretched) x: Elongation of the spring K: Force constant of the spring
Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter7: Energy Of A System
Section: Chapter Questions
Problem 7.67CP: Review. A light spring has unstressed length 15.5 cm. It is described by Hookes law with spring...
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How to find the average force constant kavg and will this apply to the others on the bottom
Transcribed Image Text:Figure 4. How to correctly measure the po
weight hanger carries the required added masses.
Table # 1: Determination of the spring constant K
g=9.80 m/s2
xo (cm) = 5.9
M₁r (8) = 16₁55
MT= M₁ + Msw
Мт
(8)
Msw
(8)
MT
(kg)
6.6.5, 0.066.5
116:52 0.11 6.5
F=W=Mrgos X=Xf-Xo
F
(N)
0
0.6517 1.7
1.1417 3.3
xf
(cm)
166.5 0.166.5 1.6317 4.9
216.2 0.2165 2.1217
% relative difference between Kavg and Ktren
Mh: Mass of the weight hanger
Msw: Mass of added slotted weights
MT: Total Mass
W: Weight of hanger plus slotted weights
38
X
(cm)
50
100
150
200
250 266,53 02. 266.5 2.6/17
Average force constant Kavg
Force constant Ktren from the slope of the trendline in the graph
X
(m)
0
0.2 0.1
0.2
6.9 55
8
brin K=
the
6517
2.5ch 0.025 45.068
You 0.09 40,7925
55 0:055
0:055 38 576 36 36 4
7.2 0.072 36.97361111
F(N)
x(m)
K
(N/m)
xo: Position of the spring's bottom (unstretched)
xf: Position of the spring's bottom (stretched)
x: Elongation of the spring
K: Force constant of the spring
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