Figure 6–22a shows a rotating shaft simply supported in ball bearings at A and D and loaded by a nonrotating force F of 6.8 kN. Using ASTM “minimum" strengths, estimate the life of the part. S= 690 MPa ut A В 6.8 kN C D 250 75 -100→ 125 10 10- For all fillets r = 3 mm - 32 -38 35 30 30 Dimensions in mm. Fig. 6–22 (a)

Mechanics of Materials (MindTap Course List)
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Author:Barry J. Goodno, James M. Gere
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Chapter2: Axially Loaded Members
Section: Chapter Questions
Problem 2.3.19P: Repeat Problem 2.3-18, but assume that the bar is made of copper alloy. Calculate the displacements...
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MECH.ENG. DESIGN 1 PART 2

Figure 6–22a shows a rotating shaft simply supported in ball bearings at A and D and
loaded by a nonrotating force F of 6.8 kN. Using ASTM “minimum" strengths, estimate
the life of the part. S = 690 MPa
ut
A
В
6.8 kN
C
D
250
75
100
125
10
10→
For all fillets
r = 3 mm
32
38
35
30
30
R1
Dimensions in mm.
|R2
Fig. 6–22 (@)
Transcribed Image Text:Figure 6–22a shows a rotating shaft simply supported in ball bearings at A and D and loaded by a nonrotating force F of 6.8 kN. Using ASTM “minimum" strengths, estimate the life of the part. S = 690 MPa ut A В 6.8 kN C D 250 75 100 125 10 10→ For all fillets r = 3 mm 32 38 35 30 30 R1 Dimensions in mm. |R2 Fig. 6–22 (@)
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