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Find an equation for the line perpendicular to the line −3x−3y=−4−3x−3y=−4 having the same y-intercept as −2x+8y=9−2x+8y=9.

Question

Find an equation for the line perpendicular to the line −3x−3y=−4−3x−3y=−4 having the same y-intercept as −2x+8y=9−2x+8y=9.

check_circleAnswer
Step 1

It is known that, let m1 and m2 be the slope of the perpendicular lines then m1×m2 = –1.

Let m, be the slope of the given line and rewrite the equation -3x -3y-4
4
into the slope intercept form as y =-x+-, then m, = -1.
3
Since the two lines ate perpendicular, the slope of the line is,
тт,
_
-1
т
т —1
7TT
help_outline

Image Transcriptionclose

Let m, be the slope of the given line and rewrite the equation -3x -3y-4 4 into the slope intercept form as y =-x+-, then m, = -1. 3 Since the two lines ate perpendicular, the slope of the line is, тт, _ -1 т т —1 7TT

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Step 2
Find the y intercept ofthe equation (x= 0)
-2(0)+8y 9
8y 9
9
9
That is, the value ofc in y =mx +c is
help_outline

Image Transcriptionclose

Find the y intercept ofthe equation (x= 0) -2(0)+8y 9 8y 9 9 9 That is, the value ofc in y =mx +c is

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