Question
Asked Mar 11, 2019
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find an integer n such that f(x)= 0 for some x between n and n+1.

f(x) = x^3 - x + 3

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Expert Answer

Step 1

Given:

The function f(x) = x3x+3.

Known fact:

Newton Rphson's method.

It is an iterative process to compute one of the root of the function.

xn+1 = xn−(f(xn)/ f’(xn))

 

Step 2

Calculation:

Substitute x= 0 in f(x) = x3x+3

 

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Step 3

Obtain the iterations as fo...

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