Question

Asked Mar 11, 2019

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find an integer n such that f(x)= 0 for some x between n and n+1.

f(x) = x^3 - x + 3

Step 1

*Given:*

The function f(x) = *x*^{3}−*x*+3.

*Known fact:*

Newton Rphson's method.

It is an iterative process to compute one of the root of the function.

*x*_{n+1} = *x*_{n}−(*f*(x_{n})/* f’*(x_{n}))

Step 2

*Calculation:*

Substitute x= 0 in f(x) = *x*^{3}−*x*+3

Step 3

Obtain the iterations as fo...

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