Find Ka value using ice tables for equilibrium help on question 2 6:00 PM Wed Mar 16* 27% 4Question 3 of 4RetryThe pH for O.0850 M solution ofCeH,CH,COOH is 2.68. Determinethe value of Ka for CH,CH,COOH.< PREV12Based on your ICE table and definition ofKa, set up the expression for Ka and thenevaluate it. Do not combine or simplifyterms.[0.0850] [0.0850]Ka =5.3 x 10-5[0.0829]Incorrect, 3 attempts remainingYour expression for Ka is incorrect. Recall the general definition ofKa for the generic acid, HA:HA(aq) + H,O(1) =H;0*(aq) + A (aq)Ka =[H;Oʻ][A]/[HA]Tap here or pull up for additional resources 6:00 PM Wed Mar 16* 27% 4Question 3 of 4RetryThe pH for O.0850 M solution ofCeH,CH,COOH is 2.68. Determinethe value of Ka for CH;CH,COOH.12NEXT>Based on the given values, fill in the ICEtable to determine concentrations of allreactants and products.CeH,CH,COOHH2O(1)H3O*(aq) C6H,CH¿COO-Initial (M)0.0850Change (M -2.1 x 102.1 x 10-32.1 x 10-3Equilibrium0.08292.1 x 10-32.1 x 10-3Incorrect, 3 attempts remainingYour expression for Ka is incorrect. Recall the general definition ofKa for the generic acid, HA:HA(aq) + H2O(1) =H;0*(aq) + A (aq)Ka = [H;O*][A]/[HA]Tap here or pull up for additional resources

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Find Ka value using ice tables for equilibrium help on question 2

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter14: Principles Of Neutralization Titrations

Section: Chapter Questions

Problem 14.33QAP

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Question

Find Ka value using ice tables for equilibrium help on question 2

6:00 PM Wed Mar 16
* 27% 4
Question 3 of 4
Retry
The pH for O.0850 M solution of
CeH,CH,COOH is 2.68. Determine
the value of Ka for CH;CH,COOH.
1
2
NEXT>
Based on the given values, fill in the ICE
table to determine concentrations of all
reactants and products.
CeH,CH,COOH
H2O(1)
H3O*(aq) C6H,CH¿COO-
Initial (M)
0.0850
Change (M -2.1 x 10
2.1 x 10-3
2.1 x 10-3
Equilibrium
0.0829
2.1 x 10-3
2.1 x 10-3
Incorrect, 3 attempts remaining
Your expression for Ka is incorrect. Recall the general definition of
Ka for the generic acid, HA:
HA(aq) + H2O(1) =H;0*(aq) + A (aq)
Ka = [H;O*][A]/[HA]
Tap here or pull up for additional resources

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