Find the AH,n for the following reaction: 2N2(9) + 502(9) → 2N2O5 (9) given the following reactions and subsequent AH° values $$ 2H2 (9) + O2(9) N2O5 (9) + H2Ou) N2(9) + 302(9) + H2 (9) 2H,O(1) 2HNO31) ΔΗ = -539.4 kJ AH° = -83.5 kJ 2HNO3) AH° = -326.6 kJ $$

Organic Chemistry
9th Edition
ISBN:9781305080485
Author:John E. McMurry
Publisher:John E. McMurry
Chapter5: Stereochemistry At Tetrahedral Centers
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Find the AHn for the following reaction:
2N2(9)
+ 502(9) → 2N2O5 (9)
given the following reactions and subsequent AH° values
$$
2H,O1)
2H2 (9) + O2 (9)
N,O5 (9) + H2Ou) → 2HNO31)
N2(9) + 302(9) + H2(9) → 2HNO3(1)
AH° = -539.4 kJ
AH° = -83.5 kJ
AH° = -326.6 kJ
$$
Transcribed Image Text:Find the AHn for the following reaction: 2N2(9) + 502(9) → 2N2O5 (9) given the following reactions and subsequent AH° values $$ 2H,O1) 2H2 (9) + O2 (9) N,O5 (9) + H2Ou) → 2HNO31) N2(9) + 302(9) + H2(9) → 2HNO3(1) AH° = -539.4 kJ AH° = -83.5 kJ AH° = -326.6 kJ $$
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