Find The critical valle T912 needed TO Construct a confidence havey Interval of the Given level with given Sample size a) For level 90% sampo Size 1 13) For level 9810 and Sample 11 C) For level as % and Sampo Size 25 D) For level 99% and samposize 14
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- Construct a 95% confidence interval of the difference in proportion of inside salespersons between Low and High experience. Observation Salary (AED) Position Experience 1 173154 Inside Low 2 145863 Inside Low 3 166896 Inside Low 4 155844 Inside Low 5 160392 Inside Low 6 158499 Inside Low 7 167877 Inside Low 8 191397 Inside Low 9 162366 Inside Low 10 176442 Inside Low 11 177828 Inside Low 12 170970 Inside Low 13 169383 Inside Low 14 148266 Inside Low 15 173010 Inside Low 16 156216 Inside Low 17 153357 Inside Low 18 169056 Inside Low 19 164673 Inside Low 20 160392 Inside Low 21 211545 Outside Low 22 186849 Outside Low 23 191568 Outside Low 24 206574 Outside Low 25 190434 Outside Low 26 192864 Outside Low 27 214035 Outside Low 28 196638 Outside Low 29 198072 Outside Low 30 183384 Outside Low 31 182979 Outside Low 32 183897 Outside Low 33 205680 Outside Low 34 201711 Outside Low 35 186675 Outside Low 36 188643…A researcher randomly selected 25 samples from natural brinjal and 27 samples from genetically modified brinjal grown at a research farm, and recorded their weight as tabulated below. On the basis of samples taken for the study, estimate whether there is a difference between population means at 95% confidence level. [Hint: Use two tailed t test assuming equal population variances]Weights of natural brinjal, in grams Weights of modified brinjal, in grams125 140 140 185 160 180130 160 165 165 145 1903126 120 135 160 150 145127 150 130 170 155 160150 155 165 180 160 170135 145 170 190 145 180140 140 130 170 140 145150 145 145 150 135160 165 130 155 185Determine the critical value zα/2zα/2 that corresponds to a 96% level of confidence.
- Assuming the two sites are hydrologically well connected, the transit time between the two sites is fast, and the two sites cannot be treated as independent samples, what kind of t-test should be performed to show that the upslope site is greater than the downslope site? Enter the letter of your answer choice in the answer blank A. one-tailed unpaired t-testB. two-tailed unpaired t-testC. one-tailed paired t-testD. two-tailed paired t-test What is the calculated t statistic, rounded to 4 decimal places? Is the calculated t statistic greater or less than the critical t value reported by the data analysis tool pack? (enter greater or less) Is the nitrate concentration at the upslope site significantly greater than the downslope site? (Enteryes or no) Based on this statistical result, and assuming no diffusion or dilution occurs between the upslope and downslope site, do you think microbes are removing NO3- from the ground water? (Enter yes or no)Based on these data, can the consumer group conclude, at the 0.05 level of significance, that the mean tread wear of Brand 2 exceeds that of Brand 1? Answer this question by performing a hypothesis test regarding μd (which is μ with a letter "d" subscript), the population mean difference in tread wear for the two brands of tires. Assume that this population of differences (Brand 1 minus Brand 2) is normally distributed.Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified. (If necessary, consult a list of formulas.) A. Find the value of the test statistic. (Round to three or more decimal places.) B. Find the critical value at the 0.05 level of significance. (Round to three or more decimal places.) C. At the 0.05 level, can the consumer group conclude that mean tread wear of Brand 2 exceeds that of Brand 1?Based on these data, can the consumer group conclude, at the 0.05 level of significance, that the mean tread wear of Brand 2 exceeds that of Brand 1? Answer this question by performing a hypothesis test regarding μd (which is μ with a letter "d" subscript), the population mean difference in tread wear for the two brands of tires. Assume that this population of differences (Brand 1 minus Brand 2) is normally distributed.Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified. (If necessary, consult a list of formulas.) A. Find the critical value at the 0.05 level of significance. (Round to three or more decimal places.)
- From a large number of actuarial exam scores, a random sample of 275 scores is selected, and it is found that 187 of these 275 are passing scores. Based on this sample, find a 90% confidence interval for the proportion of all scores that are passing. Then find the lower limit and upper limit of the 90% confidence interval.A sample of 200 bolts from one machine showed that 15 were defective, while a sample of 100 bolts from another machine showed that 12 were defective. Find the (a) 95%, (b)99.73% confidence limits for the difference in proportions of defective bolts from the two machines. Discuss the results obtained.Compute the critical value zα/2 that corresponds to a 84% level of confidence.
- A random sample of 12 female students in a certaindormitory showed an average weekly expenditure of $8.00for snack foods, with a standard deviation of $1.75. Constructa 90% confidence interval for the average amount spent eachweek on snack foods by female students living in thisdormitory, assuming the expenditures to be approximatelynormally distributed.The file FastFood contains the amount that a sample of 15 customers spent for lunch ($) at a fast-food restaurant: 7.42 6.29 5.83 6.50 8.34 9.51 7.10 6.80 5.904.89 6.50 5.52 7.90 8.30 9.60 a. Construct a 95% confidence interval estimate for the population mean amount spent for lunch ($) at a fast-food restaurant. b. Interpret the interval constructed in (a) c. What assumption must you make about the population distribu-tion in order to construct the confidence interval estimate in (a)?A random sample of 4000 U.S. citizens yielded 2250 who are in favor of gun control legislation. Estimate the true proportion of all Americans who are in favor of gun control legislation using a 99% confidence interval. a. 0.5626 +- 0.6337 b. 0.4375 +- 0.0202 c. 0.4375 +- 0.6337 d. 0.5626 +- .0202