Question

Asked Nov 19, 2019

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Find the equation of the line passing through the point (2, 3) and perpendicular to the line **2y = 6 – 3x **

Step 1

Given, a line passing through the point (2, 3) and perpendicular to the line 2y = 6 – 3x.

First rewrite the given equation into slope intercept form.

i.e, y = mx +c

Where, m is the slope and c is the y-intercept.

Step 2

Two lines are perpendicular when the product of their slope is -1.

Step 3

Then, the equation of the oth...

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