Answered: Find the instantaneous velocity of the…

Name: Find the instantaneous velocity of the particle described in the figu
Uploaded: 2024-03-05T11:56:34.000Z
Channel: Bartleby
Description: Find the instantaneous velocity of the particle described in the figure below at the following times.x(m)106.414-2-6(a) t= 0.8 sm/s(b) t- 2.9 s| m/s(c)m/s(d) t- 7.3 sm/s

Science

Physics

Find the instantaneous velocity of the particle described in the figure below at the following times. x(m) 10 6. 4 1 4 -2 -6 (a) t= 0.8 s m/s (b) t- 2.9 s | m/s (c) m/s (d) t- 7.3 s m/s

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter2: Motion In One Dimension

Section: Chapter Questions

Problem 7P: Find the instantaneous velocity of the particle described in Figure P2.1 at the following times: (a)...

See similar textbooks

Similar questions

Consider a runner moving on the positive direction with an initial Velocity of 6.4 m/s slows down at a constant rate of -0.4 m/s squared over a period of 2 seconds. What distance does she travel during this process?
A car traveling at 20 m/s when the driver sees a child standing in the road. He takes 0.80 s to react, then steps on the brakes and slows at 7.0 m/s2. How far does the car go before it stops? Please provide drawing with the solution.
A rocket of mass 1223 kg accelerates at 129 m/s^2 for 39 s from an initial speed of 1836 m/s. How fast will be the rocket be traveling after 39 s? No unit is required for the final answer.
A bolt is dropped from a bridge under construction, falling 82 m to the valley below the bridge. How much time does it take to pass through the last 17 % of its fall? a. 0.695 s b. 3.395 s c. 4.091 s d. 0.364 s
A 1.75−kg particle moves as a function of time as follows: x = 4.1cos(3.98t+π/3) where distance is measured in meters and time in seconds. Find the velocity of this particle at t = 1.45 s. Round your answer to 3 decimal places.
A particle moves according to a law of motion s = f(t), t ≥ 0, where t is measured in seconds and s in feet. f(t) = 0.01t4 − 0.03t3 (a) Find the velocity at time t (in ft/s).v(t) = (b) What is the velocity after 1 second(s)?v(1) = ft/s(c) When is the particle at rest? t = s (smaller value) t = s (larger value) (d) When is the particle moving in the positive direction? (Enter your answer using interval notation.) (e) Find the total distance traveled during the first 11 seconds. (Round your answer to two decimal places.) ft(f) Find the acceleration at time t (in ft/s2). a(t) = Find the acceleration after 1 second(s). a(1) = ft/s2 (g) Graph the position, velocity, and acceleration functions for the first 11 seconds. (h) When, for 0 ≤ t < ∞, is the particle speeding up? (Enter your answer using interval notation.) When, for 0 ≤ t < ∞, is it slowing down? (Enter your answer using interval notation.)
An object is released from rest (its initial velocity is zero) from the Empire State Buildingat a height of 1250 ft above street level. The height of the object can be modeled by theposition function s = f(t) = 1250 − 16t2 (a) Find the object’s instantaneous velocity at time t = 6 s. (b) Verify that the object is still falling at t = 5 s.
Dr. John Paul Stapp was a U.S. Air Force officer who studied the effects of extreme acceleration on the human body. On December 10, 1954, Stapp rode a rocket sled, accelerating from rest to a top speed of 282 m/s (1015 km/h) in 5.00 s and was brought jarringly back to rest in only 1.40 s. Calculate his (a) acceleration in his direction of motion and (b) acceleration opposite to his direction of motion. Express each in multiples of g (9.80 m/s2) by taking its ratio to the acceleration of gravity.
A particle P projected from a point O on horizontal ground hits the ground after 2.4 seconds.The horizontal component of the initial velocity of P is 5/3 d ms-1The speed of P as it passes over the wall is 16ms-1(d) Find the value of d correct to 3 significant figures.May I have the answer for D please as the rules is only to do 3 of them so I asked separately
A particle moves according to a law of motion s = f(t), t ≥ 0, where t is measured in seconds and s in feet. f(t) = 0.01t4 − 0.02t3 a) When, for 0 ≤ t < ∞, is the particle speeding up? (Enter your answer using interval notation.) b) When, for 0 ≤ t < ∞, is it slowing down? (Enter your answer using interval notation.)
An object is moving in positive x direction, slowing at a rate of 4.16m/s^2. After moving a distance of 49.7 meters, the speed of the object is 12.4 m/s what is the object's initial speed?
A particle is fired vertically upwards and its height, h metres, after any number of seconds, t, is given by formula h=50t-2t2 a) Find the height of particle after 2.3 seconds b) Find the speed of particle after 2.7 seconds c) What does dh/dt=0 mean in the context of the question? d) After how many seconds does the particle stop rising?