Find the length of the entire perimeter of the region inside r = 15 sin 0 but outside r = = 4. Answer:

Q: Find the area of the region outside the circle r = √3 and inside the circle r=2 cos∝.

A:

Q: Find the length of the entire perimeter of the region inside 15 sin 0 but outside r = 1.

A: The region is inside r=15sin θ but outside the r = 1

Q: Find the area of the region inside one leaf of the three-leaved rose r= 5 cos 30.

A: In the question it is asked to calculate area inside one leaf.

Q: Find the area of the region inside: r = 5 sin 0 but outside: r = 1.

A: We will use double integration to solve this

Q: Find the area of the region inside r 8 sin 0 but outside r = 4.

A: Given. r = 8sin a r = 4 We need to calculate the area between the 2 curves

Q: Find the area of the region Inside one leaf of the four-leaved rose r = cos 2u

A: Given:  r = cos 2u

Q: Find the area that is inside the cardioid r= 3+2 sinθ but outside of the circle r= 4

A:

Q: Find the area of the region inside the circle r = 12sinθ and outside the cardioid r = 4 + 4 sinθ.

A: Area

Q: Find the length of the entire perimeter of the region inside r = 18 sin but outside r = 3.

A:

Q: Find the area of the region that lies inside both curves. r = 9 + cos(?),    r = 9 − cos(?)

A:

Q: Find the area of the region that lies inside the first curve and outside the second curve. r= 16…

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Q: Find the area of the described region. region enclosed by one petal of  r = 6 cos(4?)

A: A=integration a to b 1/2r^2d(thita)

Q: I need solutions in 10 minutes please. Q/Find the area of ​​region enclosed by the(r=1+cosθ)

A: Solution is in step 2

Q: Find the area of the region One petal of r = 2 sin 6θ

A: Now the graph is,

Q: Find the length of arc XY with the given diameter. Leave answer in terms of TT. * 45 Y. 24cm

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Q: Find the area of the region enclosed by one loop of the curve. r = 8 sin(30)

A:

Q: Find the area of the region inside: r = 6 sin 0 but outside: r = 2

A:

Q: Find the area of the region that lies inside both curves. r = 5 + 3 sin(?),    r = 5 + 3 cos(?)

A: The area between two polar curves, say r=f(θ)  and  r=g(θ), within the limits θ=α  to  θ=β is given…

Q: Find the area of the region inside the circle r=5sinθ and outside the limacon r=2+sinθ

A:

Q: Find the area inside r=1+sin θ and outside r=3sin θ.

A: Concept: The calculus helps in understanding the changes between values that are related by a…

Q: Find the area of the region. Inside r = 2a cos θ and outside r = a

A: We have to find the area of the region inside r=2acosθ and outside r=a

Q: Find the area of the region outside r = 5 + 5 sin 0 , but inside r = 15 sin 0.

A:

Q: a. Use integrals to show that the circumference of the circle x2 + y? a? is 2na. %3D b. Find the…

A: Solving question (a),

Q: Find the area. Sin 9in BD = 6in B. A,

A: Use formula of area of triangle

Q: SA = 6 in. 6 in. V = 10 in. 6 in.

A:

Q: Find the area pebal r=4 sin C30) of one

A: Let's now plot the graph:

Q: Find the area of the region that is outside r=2 and inside r=4 sin(theta)

A: Solution : We have to given two curves r = 2 and r = 4sinθ and we have to find out the area outside…

Q: Find the area of the region inside 2 petals of the rose r = sin 80

A: Solution :-

Q: A fuel oil tank is an upright cylinder, buried so that its circular top is 8ft beneath ground level.…

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Q: Find the area enclosed by r = 2 sin 30.

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Q: A conical paper cup is to have a height of 3 inches. Find the radius r of the cone that will result…

A: We need to find the radius of the cone  Given height (h) and the surface area (Pi*r*l)

Q: Find the area of the region inside the circle r=-4sin(theta) and outside the circle r=2

A: Given, the area of the regionis inside the circle r=-4sinθand out side the circle r=2.

Q: Find the area of the region inside the circle r= 32 cos 0 and to the right of the vertical line r= 8…

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Q: Find the length of the entire perimeter of the region inside r=14 sin 0 but outside r 2. %3D Answer:

A: Given inside r=14sinθ outside r=2

Q: Find the area of the region inside: r = 7 sin 0 but outside: r = 1

A:

Q: Find the length of the entire perimeter of the region inside r = 6 sin 0 but outside r = 3.

A: Given the equation of the polar curve is, r=6sinθ Solving the equation r=6sinθ and r=3 for θ,…

Q: Find the exact area inside r = 6 sin 0 and outside r = 3.

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Q: Find the area of the region enclosed by one loop of the curve. r = 8 sin(50)

A:

Q: Find the length of the entire perimeter of the region inside r = 14 sin 0 but outside r = 2. Answer:

A: Given the region r=14sinθ and r=2. We need to find the length of the entire perimeter inside…

Q: Find the area of the region enclosed by one loop of the curve r = sin(60) 36

A: I am attaching image so that you understand each and every step.

Q: Find the length of the entire perimeter of the region inside 15 sin 0 but outside r = 4.

A: Concept Used: Arc length formula Arc length l=∫abr2+drdθ2dθ

Q: Find the area of the specified region. Inside the circle r=6 and to the right of the line r= 3 sec 0

A: Given problem is :

Q: Find the area of the region inside: r = 7 sin 0 but outside: r = 3

A: I am going to solve the given problem by using some simple  calculus to get the required result.

Q: Find the area of the region inside: r 10 sin 0 but outside: r = 1

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Q: Find the area of the sector bound by the radii EF,EDand arc FD if the radius is 4 and MZFED = 40…

A: Given data: The given radius of the circle is EF=r=4 units. The given angle made by the sector is θ=…

Q: Find the length of the entire perimeter of the region inside r = 6 sin 0 but outside r = 1.

A: Given that  r=6sintheta and r=1 To find the length of the entire perimeter of the region

Q: 2. Find the length of the entire perimeter of the region inside r = 14 sin 0 but outside r = %3D…

A:

Q: LA = .SA = 24 in. 36 in. 36 in,

A: Fir find out the lateral height then use the formula for each quantity.

Q: Find the area that it encloses. r = 2 − 2 sin(?)

A: To find: The area that encloses r = 2 − 2 sin(?). Graph: The polar curve  over the interval [0,2pi]…

Q: Find the areas of the regions Inside the oval limaçon r = 4 + 2 cos θ

A: