Find the lower bound of the confidence interval, rounding the result to four decimal places.Р(1 — р)p - E = P – Z«j2\%3D0.57(1 – 0.57)= 0.571.9601,007Find the upper bound of the confidence interval, rounding the result to four decimal places.P(1 — р)p + E :p + z0.57(1 – 0.57)= 0.57 + 1.9601,007Therefore, a 95% confidence interval for the population proportion of adults who lack confidence they will be able to afford health insurance in the future is from alower bound ofX to an upper bound of

Given Sample proportion p=0.57 Sample size =1007 We have to find 95% confidence interval for the…

Find the lower bound of the confidence interval, rounding the result to four decimal places. p(1 – p) p- E = P - z n 0.57(1 – 0.57) = 0.57 - 1.960 1,007 Find the upper bound of the confidence interval, rounding the result to four decimal places. P(1 – p) p+ E = P + Za/2/ n 0.57(1 – 0.57) 1,007 = 0.57 + 1.960 Therefore, a 95% confidence interval for the population proportion of adults who lack confidence they will be able to afford health insurance in the future is from a lower bound of X to an upper bound of X .

Find the lower bound of the confidence interval, rounding the result to four decimal places. p(1 – p) p- E = P - z n 0.57(1 – 0.57) = 0.57 - 1.960 1,007 Find the upper bound of the confidence interval, rounding the result to four decimal places. P(1 – p) p+ E = P + Za/2/ n 0.57(1 – 0.57) 1,007 = 0.57 + 1.960 Therefore, a 95% confidence interval for the population proportion of adults who lack confidence they will be able to afford health insurance in the future is from a lower bound of X to an upper bound of X .

ENGR.ECONOMIC ANALYSIS

14th Edition

ISBN:9780190931919

Author:NEWNAN

Publisher:NEWNAN

Chapter1: Making Economics Decisions

Section: Chapter Questions

Problem 1QTC

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