Find the molar conductivity according to these data and draw a graph. KCI (mol/dm^3) x(s/cm)0.1L(s).K(1/cm)1.0.111730.118609 0.9422.0.010.012880.013586 0.9483.0.020.023156 0.024687 0.944.0.0010.001411 0.001486 0.949K1=0.1117 s/cm / 0.118609 s = 0.942 1/cmK2=0.01288 s/cm / 0.013586 s = 0.948 1/cmK3=0.023156 s/cm / 0.023687 s = 0.937 ~0.940 1/cmK4=0.001411 s/cm / 0.001486 s = 0.949 1/cmKl=K2=K3=K4=K M9SO4.7H2O(mol/dm^3)L(s)K(1/cm)1.0.20.0309160.94145.312.0.10.017470.94164.223.0.050.0094230.94177.154.0.0250.0049230.94185.105.0.01250.0025670.94193.04^=1000KXL/C^1= 1000x0.94x0.030916/0.2= 145.31^2=1000x0.94x0.01747/0.1= 164.22^3=1000x0.94x0.09423/0.05=177.15^4=1000x0.94x0.04923/0.025=185.10^5=1000x0.94x0.002567/0.0125=193.04

The formula for calculating molar conductivity is: -----(1)

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Find the molar conductivity according to these data and draw a graph.

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter32: Radiochemical Methods

Section: Chapter Questions

Problem 32.12QAP

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Question

100%

Find the molar conductivity according to these data and draw a graph.

KCI (mol/dm^3) x(s/cm)
0.1
L(s).
K(1/cm)
1.
0.11173
0.118609 0.942
2.
0.01
0.01288
0.013586 0.948
3.
0.02
0.023156 0.024687 0.94
4.
0.001
0.001411 0.001486 0.949
K1=0.1117 s/cm / 0.118609 s = 0.942 1/cm
K2=0.01288 s/cm / 0.013586 s = 0.948 1/cm
K3=0.023156 s/cm / 0.023687 s = 0.937 ~0.940 1/cm
K4=0.001411 s/cm / 0.001486 s = 0.949 1/cm
Kl=K2=K3=K4=K

M9SO4.7H2O(mol/dm^3)
L(s)
K(1/cm)
1.
0.2
0.030916
0.94
145.31
2.
0.1
0.01747
0.94
164.22
3.
0.05
0.009423
0.94
177.15
4.
0.025
0.004923
0.94
185.10
5.
0.0125
0.002567
0.94
193.04
^=1000KXL/C
^1= 1000x0.94x0.030916/0.2= 145.31
^2=1000x0.94x0.01747/0.1= 164.22
^3=1000x0.94x0.09423/0.05=177.15
^4=1000x0.94x0.04923/0.025=185.10
^5=1000x0.94x0.002567/0.0125=193.04

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