E = h vE = hc / wavelenegthwavelength = c / vc = 3.00 x 108 m /sh = 6.626 x 10-34 J. s1 nm = 1 x 10-9 mAvogadro's number: 6.022 x 1023total electron groupgroup geometrynumber of surrounded atoms number of lone pair of electronsmolecular shape 2linear 20linear 3trigonal planar 3 20 1trigonal planar bent or angular 4 tetrahedral 4 3 2 0 1 2 tetrahedral trigonal pyramidal bent or angular Find the noble gas having the same electronic configuration with Sr+2.Z of Sr = 38Group of answer choicesA.) XeB.) NeC.) Br -D.) Kr

Atomic number of Sr = 38 Sr has total 38 electrons

Answered: Find the noble gas having the same…

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter10: Molecular Structure And Bonding Theories

Section: Chapter Questions

Problem 10.99QE: The molecular orbital diagram of NO shown in Figure 10.47 also applies to the following species....

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E = h v

E = hc / wavelenegth

wavelength = c / v

c = 3.00 x 10⁸ m /s

h = 6.626 x 10^-34 J. s

1 nm = 1 x 10^-9 m

Avogadro's number: 6.022 x 10²³

total electron group	group geometry	number of surrounded atoms	number of lone pair of electrons	molecular shape
2	linear	2	0	linear
3	trigonal planar	3 2	0 1	trigonal planar bent or angular
4	tetrahedral	4 3 2	0 1 2	tetrahedral trigonal pyramidal bent or angular

Find the noble gas having the same electronic configuration with Sr⁺².

Z of Sr = 38

Group of answer choices

A.) Xe

B.) Ne

C.) Br -

D.) Kr

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