Find the resultant of two forces shown in Figure and its direction with X axis using Sine and Cosine Laws? Y 18° 900 KN 22° 750 kN X
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- Solve for the magnitude of the resultant and the direction cosines of the following cartesian vectors. A: 55i + 63j - 16kFind the resultant and angle of direction based on the horizontal. using tail to tip method A) 58 km 30 oS of E B) 22 km 42 oW of S C) 18 km 41 oS of E D) 24 km 29 oW of S E) 12 km West F ) 30 km 24 oW of NA force of 800 kN is applied at point B and is directed towards point F. The Force at D = 0 and does not apply. Determine the component of the force that acts in the direction of line BE. Write this component as a Cartesian vector. The answer is (299i-598j+199k) kN, please show in depth how to solve.
- a = 4 mb = 3.2 mc = 2 mF = {-7i+4j+12k} NSpecified axis: AF Find the magnitude of the moment of F about the specified axis.If the calculated answer is not whole number, express it in 4 significant figures.the vector A= - 2x - y + 9z is firstly rotated +180 degrees around x-axis then Transformed by 2x+4y+z amount. Find the resultant vector.Two forces act on the pipe assembly as shown in the figure. Determine the following: 3.1 The magnitude of the resultant FR is Blank 1 lb. 3.2 The coordinate direction angle Alpha of FR is Blank 2°. 3.3 The coordinate direction angle Beta of FR is Blank 3°. 3.4 The coordinate direction angle Gamma of FR is Blank 4°.
- For the forces F and G, where: F is a force of magnitude 25N acting in direction i - 4j + 8k G is a force of magnitude 70 N acting in direction 2i + 3j - 6k (A) If G acts at the point (5, 2, 3), calculate the magnitude of the vector moment of G about the point (6,7, 25). Give your answer to two decimal places. (B) Calculate the magnitude R of the resultant force R = F + G. Give your answer in N, to two decimal places.Find the component of the force F = -7i + 8j – 9k lb along the line through the origin makingequal acute angles with the coordinate axes.Find the resultant and direction of the following forces using the graphical method: F1 = 20 N, 30 degrees NE, F2 = 15 N, 50 degrees NW, 10 N, south
- Given in the figure, the wind forces are perpendicular with respect to the inclined member of truss. Find the following: Magnitude of the resultant vector Location of the resultant vector for point Aa. What is the position vector that starts at -50j and ends at 50 j? b. What is the position vector that starts at (-50 i - 20 j +10 k) lb and ends at (50 i + 20 j -10 k) lb c. What is the resultant sum of the moments in Cartesian vector form? Round your entries to the nearest whole number.1. Vector 1 is 30 m/s at 300° and Vector 2 is 80 m/s at 50°. Direction at CCW due East.a) Calculate the resultant vector using Pythagorean theorem and/or trigonometry.