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Find the solution of the initial-value problem y'" — 7y" + 16y' — 112y = sec 4t, y(0) = 2, y'(0) - y₂(t) = = A fundamental set of solutions of the homogeneous equation is given by the functions: y₁(t)= eat, where a = Y3(t) = A particular solution is given by: Y(t) = [ S "(0) = 131 2 + 1 = = ½ › y″(0) ds- y₁(t) ]). y2(t) 1) · y3(t)

Find the solution of the initial-value problem y'" — 7y" + 16y' — 112y = sec 4t, y(0) = 2, y'(0) - y₂(t) = = A fundamental set of solutions of the homogeneous equation is given by the functions: y₁(t)= eat, where a = Y3(t) = A particular solution is given by: Y(t) = [ S "(0) = 131 2 + 1 = = ½ › y″(0) ds- y₁(t) ]). y2(t) 1) · y3(t)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Find the solution of the initial-value problem 2 y'" — 7y" + 16y' — 112y = sec 4t, y(0) = 2, y'(0) = ½ › y″(0) = 1/2, 3²(0) = 131 A fundamental set of solutions of the homogeneous equation is given by the functions: y₁(t)= eat, where a = y₂(t) = = Y3(t) = A particular solution is given by: Y(t)= - - to + Therefore the solution of the initial-value problem is: y(t) ds- y₁(t) ]). y2(t) ]) · y3(t) +Y(t)
Transcribed Image Text:Find the solution of the initial-value problem 2 y'" — 7y" + 16y' — 112y = sec 4t, y(0) = 2, y'(0) = ½ › y″(0) = 1/2, 3²(0) = 131 A fundamental set of solutions of the homogeneous equation is given by the functions: y₁(t)= eat, where a = y₂(t) = = Y3(t) = A particular solution is given by: Y(t)= - - to + Therefore the solution of the initial-value problem is: y(t) ds- y₁(t) ]). y2(t) ]) · y3(t) +Y(t)
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