Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that R,(x) → 0.] f(x) = xª – 3x²+3, a = 1 ) "(x - 1)^ = 1 – 2(x – 1) + 3(x – 1)2 + 4(x – 1)³ + (x – 1)ª n! n = 0 PA(x – 1)^ = -1 – 2(x – 1) + 3(x = 1)² - 4(x – 1)3 + (x – 1)ª n! n = 0 Os ")(x – 1)^ = 1 – 2(x – 1) + 4(x – 1)2 + 3(x - 1)³ + (x - 1)ª. n! n= 0 "(1)(x - 1)^ = -1 + 2(x – 1) + 3(x – 1)2 + 4(x = 1)³ + (x – 1)4 n! Os ")(x - 1)^ = 1 – 2(x – 1) = 4(x = 1)² + 3(x – 1)3 = (x – 1)ª n!

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