Carry out the substitution x = sin 0 in the Taylor series 1.3.5..(2n - 1) x2n+1 arcsin x = x + 2 2.4.6..(2n) 2n +1 n=1 valid for |x| < 1 and use the formula • 7/2 2.4. (2n) 2n+ 0 de = ... 3.5.. (2n + 1)'

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