Question
Asked Oct 25, 2019
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Find the​ z-scores that separate the middle 48​%of the distribution from the area in the tails of the standard normal distribution.
The​ z-scores are?
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Step 1

Computation of probability of the area above and below the 48% of the distribution from the area:

From the given information, middle area is 48%.

Since it is a standard normal di...

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P(-2Z<)048 (1-0.48) 2 0.26 Thus, P(Z<-) 0.26 P(Z>z) 1-0.26 0.74

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