Flower color in petunias is determined by the biochemical pathway shown below: B → Orange A C_ Yellow Green Blue aa bb 66 Plants of genotype AAbbcc were mated to plants of genotype AaBbCc. Determine the phenotypic ratio expected from this cross and fill in the spaces in the ratio below with whole numbers in lowest form. If none are expected in a class, then type the number 0 in the space. Yellow: Orange : Green Blue
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- In sweet peas, the given enzymatic pathway result to pigment formation in the flowers: A dihybrid plant is crossed to a white one which is heterozygous at the “C” locus (provided in the image). What is the genotype of the dihybrid plant? What is the genotype of the white plant? What kinds of flowers, colored or white, are to be expected from the cross above? Include the ratio.The purple colour results from the formation of a purple pigment in the skin of the kernel. The gene locus for the colour trait is designated “R”. The wrinkled phenotype arises from a decrease in the amount starch produced within the kernel. The gene locus for the texture trait is designated “S”. Present the data as monohybrids (Xx, XX, xx) for all five corn cobs andfor the plant. Present the colour and texture phenotypes with their associated genotypes in separate tables. Your first table should include the corn ID, the number of purple kernels, the number of yellow kernels, and the phenotypic ratio between the two kernel colours. Present the texture results in the same format to a separate table. What is the dominant phenotype for kernel colour in your assigned cornplant? What is the dominant phenotype for kernel texture in your assigned cornplant?In an intra-species cross performed in mustard plants of two different species (Brassica juncea and Brassica oleracea), a tall plant (TT) was crossed with a dwarf (tt) variety in each of the two species. The members of the F1 generation were crossed to produce the F2 generation. Of the F2 plants, Brassica juncea had 60 tall and 20 dwarf plants, while Brassica oleracea had 100 tall and 20 dwarf plants. Use chi-square analysis to analyze these results.
- The trait for medium-sized leaves in iris is determined by the genetic condition PP'. Plants with large leaves are PP, whereas plants with small leaves are P'P'. The trait for red flowers is controlled by the genes RR, pink by RR', and white by R'R'. A cross is made between two plants each with medium-sized leaves and pink flowers. If they produce 640 seedlings, what would be the expected phenotypes, and in what numbers would they be expected? View keyboard shortcuts EditViewInsertFormatToolsTable 12pt ParagraphIn tomatoes, regular leaves (L) are multilobed and serrated and potato leaves (l) are broad, smooth, and single (Image 1). Red fruit (F) is dominant to yellow fruit (f). A cross is carried out between two pure lines of tomato plants, one having regular leaves and red fruit and the other having potato leaves and yellow fruit. The F1 generation all have regular leaves and red fruit. The F1individuals are then crossed with one another. The information below represents two sets of data collected from the above cross. Phenotypes Data Set 1 Data Set 2 Regular Red 26 846 Regular Yellow 15 273 Potato Red 6 287 Potato Yellow 12 94 Total 59 1 500 Convert the expected phenotype ratio into the expected probability for each of the four phenotypes and record them in the table below. (Record your answers as a value between 0 and 1 rounded to two decimal places.) Example of calculating expected probability:To convert from the expected phenotypic ratio to the expected probability…The trait for medium-sized leaves in iris is determined by the genetic condition PP'. Plants with large leaves are PP, whereas plants with small leaves are P'P'. The trait for red flowers is controlled by the genes RR, pink by RR', and white by R'R'. A cross is made between two plants each with medium-sized leaves and pink flowers. If they produce 640 seedlings, what would be the expected phenotypes, and in what numbers would they be expected?
- In a variety of newly discovered rose plant, flowers are either white or red. Two genes were discovered to control flower color. Both genes, A and B, work in tandem in a biochemical pathway, and dominant forms of both genes are required for red flowers. A doubly-homozygous red-flowered plant is crossed with a doubly-homozygous white-flowered plant. The F1 offspring all have red flowers and are self-crossed to produce the F2. Determine the ratios of phenotypes in the F2 generation.In the Primula plant, the blue flower color is due to malvidin, a pigment encoded by the completely dominant gene (M). Presence of only the recessive gene (m) leads to white flowers. The P locus controls pigment synthesis in the M locus such that dominant gene (P) stops pigment production, and recessive gene (p) allows pigment production. Two plants both having the MmPp genotype were crossed. Answer the following questions and show complete solutions to support your answers. Use the branching method whenever applicable. a. What is the phenotypic ratio of the offspring?b. What type of gene interaction is exhibited by the flower color in Primula?c. What would be the probability of getting plants that are pure-breeding for blue flower color?In sweet peas, the synthesis of purple anthocyanin pigment in the petals is controlled by two genes, B and D. What petal color would you expect in a pure breeding plant unable to catalyze the first reaction? Indicate the genotype and phenotype. 2. What petal color would you expect in a pure breeding plant unable to catalyze the second reaction? Indicate the genotype and phenotype. 3. If plants 1 and 2 are crossed, what petal color would the F1 plants have? Indicate the genotype and phenotype. 4. What ratio of purple : blue : white plants would you expect in the F2? Indicate the genotypes, phenotypes, and the F2 phenotypic ratio.
- A plant believed to be heterozygous for a pair of alleles B/b (where B encodes yellow and b encodes bronze) was selfed, and, in the progeny, there were 280 yellow and 120 bronze plants. Do these results support the hypothesis that the plant is B/b?In sweet pea plants, the trait for purple flowers (P) is dominant to the trait for red flowers (p).Similarly, the trait for long pollen (L) is dominant to the trait for round pollen (l).Two heterozygotes are crossed, yielding the following frequencies for the F1 generation:293 purple long plants;19 purple, round plants ;28 red, long plants ;87 red, round plantsUse the chi-square test to determine if these results are due to independent assortment. detailed explanation ?Consider the following hypothetical gene a plant. Gene T produces a protein that impacts stem length. There are two alleles for gene T, T which produces long stems and t which results in short stems. If gene T displays incomplete dominance, which of the following genotypes above would have a different phenotype? and What would the phenotype be for this genotype?