You obtain two plants, one that is homozygous wild-type at locus B and one that is homozygous for a mutation at locus B. You cross the two plants (the parental generation) to get the F1 generation. If the wild-type allele at locus B is haploinsufficient, you would expect to see the. F1 generation. If the wild-type allele at locus B is haplosufficient, you would expect to see the phenotype in the phenotype in the F, generation. incompletely penetrant; normally inherited O mutant; wild-type codominant; normally inherited lethal ; dominant wild-type; mutant

You obtain two plants, one that is homozygous wild-type at locus B and one that is homozygous for a mutation at locus B. You cross the two plants (the parental generation) to get the F1 generation. If the wild-type allele at locus B is haploinsufficient, you would expect to see the. F1 generation. If the wild-type allele at locus B is haplosufficient, you would expect to see the phenotype in the phenotype in the F, generation. incompletely penetrant; normally inherited O mutant; wild-type codominant; normally inherited lethal ; dominant wild-type; mutant

BIOLOGY:CONCEPTS+APPL.(LOOSELEAF)

10th Edition

ISBN:9781305967359

Author:STARR

Publisher:STARR

Chapter13: Patterns In Inherited Traits

Section: Chapter Questions

Problem 6GP: In sweet pea plant, an allele for purple flowers (P) is dominant when paired with a recessive allele...

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In a species of plant, two genes control flower color. The red allele(R) is dominant to the white allele (r); the color-producing allele(C) is dominant to the non-color-producing allele (c). You suspectthat either an rr homozygote or a cc homozygote will producewhite flowers. In other words, rr is epistatic to C, and cc is epistatic to R. To test your hypothesis, you allow heterozygous plants(RrCc) to self-fertilize and count the offspring. You obtain the following data: 201 plants with red flowers and 144 with white flowers. Conduct a chi square analysis to see if your observed data areconsistent with your hypothesis.
. A true-breeding strain of Virginia tobacco has dominantalleles determining leaf morphology (M), leaf color(C), and leaf size (S). A Carolina strain is homozygousfor the recessive alleles of these three genes. Thesegenes are found on the same chromosome as follows:M C S6 m.u. 17 m.u.An F1 hybrid between the two strains is now backcrossedto the Carolina strain. Assuming no interference:a. What proportion of the backcross progeny willresemble the Virginia strain for all three traits?b. What proportion of the backcross progeny willresemble the Carolina strain for all three traits?c. What proportion of the backcross progeny will havethe leaf morphology and leaf size of the Virginiastrain but the leaf color of the Carolina strain?d. What proportion of the backcross progeny will havethe leaf morphology and leaf color of the Virginiastrain but the leaf size of the Carolina strain?
. In the tiny model plant Arabidopsis, the recessive allele hyg confers seed resistance to the drug hygromycin, and her, a recessive allele of a different gene, confers seed resistance to herbicide. A plant that was homozygous hyg/hyg ⋅ her/her was crossed with wild type, and the F1 was selfed. Seeds resulting from the F1 self were placed on petri dishes containing hygromycin and herbicide.a. If the two genes are unlinked, what percentage of seeds are expected to grow?b. In fact, 13 percent of the seeds grew. Does this percentage support the hypothesis of no linkage? Explain. If not, calculate the number of map units between the loci.c. Under your hypothesis, if the F1 is testcrossed, what proportion of seeds will grow on the medium containing hygromycin and herbicide?
In a certain plant, leaf size is determined by fourgenes whose alleles assort independently and actadditively. Thus, alleles A, B, C, and D each add4 cm to leaf length and alleles A′, B′, C′, andD′ each add 2 cm to leaf length. Therefore,an AA BB CC DD plant has leaves 32 cm longand an A′A′ B′B′ C′C′ D′D′ plant has leaves16 cm long.a. If true-breeding plants with leaves 32 cm longare crossed to true-breeding plants with leaves16 cm long, the F1 will have leaves 24 cm longand the genotype AA′ BB′ CC′ DD′. Listall possible leaf lengths and their expectedfrequencies in the F2 generation produced fromthese F1 plants.
In a species of plant, two genes control flower color. The redallele (R) is dominant to the white allele (r); the color-producingallele (C) is dominant to the non-color-producing allele (c). Yoususpect that either an rr homozygote or a cc homozygote willproduce white flowers. In other words, rr is epistatic to C, andcc is epistatic to R. To test your hypothesis, you allowed heterozygousplants (RrCc) to self-fertilize and counted the phenotypesof the offspring. You obtained the following data: 201 plantswith red flowers and 144 with white flowers. Conduct a chisquare test to see if your observed data are consistent with yourhypothesis.
In onions, presence of gene C causes production of an enzyme which catalyzes theproduction of bulb-color pigment. Gene K prevents this enzyme from functioning, thuspreventing enzyme production. The two genes are inherited independently. A true breedingcolored variety is crossed with a white one of genotype ccKK. (b) Another pair of alleles R and r, independent of genes C and K controls the specific color for bulbs, R giving red and r, yellow bulbs. If the true-breeding colored variety are homozygous for R and the white ones homozygous for r, what would be the phenotypic ratios in the F1 and F2 of the above cross?
Two wheat plants that are heterozygous for recessive alleles a and bare crossed. Both parents carry recessive alleles a and b in cisconfiguration What frequency of a b+ /a+ b progeny will appear if a and b are 12 map units apart?
In corn, the genes for tassel length (alleles T and t) andrust resistance (alleles R and r) are known to be on separate chromosomes. In the course of making routinecrosses, a breeder noticed that one T/t ; R/r plant gaveunusual results in a testcross with the double-recessivepollen parent t/t ; r/r. The results wereProgeny: T/t ; R/r 98t/ t ; r/r 104T/t ; r/r 3t/t ; R/r 5Corncobs: Only about half as many seeds as usuala. What key features of the data are different from theexpected results?b. State a concise hypothesis that explains the results.c. Show genotypes of parents and progeny.d. Draw a diagram showing the arrangement of alleleson the chromosomes.e. Explain the origin of the two classes of progenyhaving three and five members.
. In a particular kind of ornamental flower, the wildtype flower color is deep purple, and the plants aretrue-breeding. In one true-breeding mutant stock, theflowers have a reduced pigmentation, resulting in alavender color. In a different true-breeding mutantstock, the flowers have no pigmentation and are thuswhite. When a lavender-flowered plant from the firstmutant stock was crossed to a white-flowered plantfrom the second mutant stock, all the F1 plants hadpurple flowers. The F1 plants were then allowed toself-fertilize to produce an F2 generation. The 277 F2plants were 157 purple : 71 white : 49 lavender. a. Explain how flower color is inherited. Is this traitcontrolled by the alleles of a single gene?b. What kinds of progeny would be produced if lavender F2 plants were allowed to self-fertilize?
Hemophilia and color blindness are both recessive conditions caused by genes on the X chromosome. To calculate the recombination frequency between the two genes, you draw a large number of pedigrees that include grandfathers with both hemophilia and color blindness, their daughters (who presumably have one chromosome with two normal alleles and one chromosome with two mutant alleles), and the daughters sons. Analyzing all the pedigrees together shows that 25 grandsons have both color blindness and hemophilia, 24 have neither of the traits, 1 has color blindness only, and 1 has hemophilia only. How many centimorgans (map units) separate the hemophilia locus from the locus for color blindness?
In sweet pea plant, an allele for purple flowers (P) is dominant when paired with a recessive allele for red flowers (p). An allele for long pollen grains (L) is dominant when paired with a recessive allele for round pollen grain (l). Bateson and Punnett crossed a plant having purple flowers/long pollen grains with one having white/flowers/round pollen grains. All F1 offspring had purple flowers and long pollen grains. Among the F2 generation, the researchers observed the following phenotypes: 296 purple flowers/long pollen grains 19 purple flowers/round pollen grains 27 red flowers/long pollen grains 85 red flowers/round pollen grains What is the best explanation for these results?
The text outlines some of the problems Frederick William I encountered in his attempt to breed tall Potsdam Guards. a. Why were the results he obtained so different from those obtained by Mendel with short and tall pea plants? b. Why were most of the children shorter than their tall parents?