Please breakdown the solution in the same format below.Thank you! For a 25.0 % m/v MgCl₂ solution, what is the molarity? In problem 2 we determined that this is a 2.63 M solution.First we have to convert moles into equivalentsMgCl22 CI-11 mol =Mg+2 +a. 250.j. 1p. 1.80 x 10-²W. 106b. 100.0k. 6.00 x 10-3molX. 10³q. 7.65 x 10-10y. 95.21equivalents-)(-c. 2I. 3.60 x 10-²d. 30.00r. 2.63m. 6.00 x 10-3s. 7.89Z. 10eqmole. 6 f. 24=g. 3n. 5t. 5.26h. 36o. 3.0 x 10-²u. 1012i. 18.0V. 10⁹eq/L

25% m/v MgCl2 solution is provided. To calculate its Molarity and express in eq/L.

For a 25.0 % m/v MgCl₂ solution, what is the molarity? In problem 2 we determined that this is a 2.63 M solution. First we have to convert moles into equivalents MgCl2 Mg+2 + 2 CI-1 1 mol = a. 250. b. 100.0 j. 1 k. 6.00 x 10-3 p. 1.80 x 10-² W. 106 mol X. 10³ L c. 2 q. 7.65 x 10-10 y. 95.21 equivalents -)(- d. 30.00 1. 3.60 x 10-² r. 2.63 e. 6 m. 6.00 x 10-3 s. 7.89 Z. 10 eq mol f. 24 )= g. 3 n. 5 t. 5.26 h. 36 o. 3.0 x 10-² u. 1012 i. 18.0 V. 10⁹ eq/L

For a 25.0 % m/v MgCl₂ solution, what is the molarity? In problem 2 we determined that this is a 2.63 M solution. First we have to convert moles into equivalents MgCl2 Mg+2 + 2 CI-1 1 mol = a. 250. b. 100.0 j. 1 k. 6.00 x 10-3 p. 1.80 x 10-² W. 106 mol X. 10³ L c. 2 q. 7.65 x 10-10 y. 95.21 equivalents -)(- d. 30.00 1. 3.60 x 10-² r. 2.63 e. 6 m. 6.00 x 10-3 s. 7.89 Z. 10 eq mol f. 24 )= g. 3 n. 5 t. 5.26 h. 36 o. 3.0 x 10-² u. 1012 i. 18.0 V. 10⁹ eq/L

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter10: Solutions

Section: Chapter Questions

Problem 78QAP: A gaseous solute dissolves in water. The solution process has H=15 kJ. Its solubility at 22C and...

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