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For each graph below, find an Euler trail in the graph or explain why the graph does not have an Euler trail. (Hint: One way to find an Euler trail is to add an edge between two vertices with odd degree, find an Euler circuit in the resulting graph, and then delete the added edge from the circuit.) b a (i) Figure 11: An undirected graph has 6 vertices, a through f. 5 vertices are in the form of a regular pentagon, rotated 90 degrees clockwise.

For each graph below, find an Euler trail in the graph or explain why the graph does not have an Euler trail. (Hint: One way to find an Euler trail is to add an edge between two vertices with odd degree, find an Euler circuit in the resulting graph, and then delete the added edge from the circuit.) b a (i) Figure 11: An undirected graph has 6 vertices, a through f. 5 vertices are in the form of a regular pentagon, rotated 90 degrees clockwise.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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(c) For cach graph below, find an Euler trail in the graph or explain why the graph does not have an Euler trail. (Hint: One way to find an Euler trail is to add an cdge between two vertices with odd degree, find an Euler circuit in the resulting graph, and then delete the added edge from the circuit.) (i) Figure 11: An undirected graph has 6 vertices, a through f. 5 vertices are in the form of a regular pentagon, rotated 90 degrees clockwise. Hence, the top vertez becomes the rightmost vertez. From the bottom left vertez, moving clockwise, the vertices in the pentagon shape are labeled: a, b, c, e, and f. Vertez d is above vertez e, below and to the right of vertez c. Undirected edges, line segments, are between the following vertices: a and b; a and e; a and d; a and f; b and f; b and e; e and d; e and f; d and e; and d and f.
Transcribed Image Text:(c) For cach graph below, find an Euler trail in the graph or explain why the graph does not have an Euler trail. (Hint: One way to find an Euler trail is to add an cdge between two vertices with odd degree, find an Euler circuit in the resulting graph, and then delete the added edge from the circuit.) (i) Figure 11: An undirected graph has 6 vertices, a through f. 5 vertices are in the form of a regular pentagon, rotated 90 degrees clockwise. Hence, the top vertez becomes the rightmost vertez. From the bottom left vertez, moving clockwise, the vertices in the pentagon shape are labeled: a, b, c, e, and f. Vertez d is above vertez e, below and to the right of vertez c. Undirected edges, line segments, are between the following vertices: a and b; a and e; a and d; a and f; b and f; b and e; e and d; e and f; d and e; and d and f.
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