For each of the equations, determine the change in the number of moles of gas, Δ?gasΔngas. (NH4)2CO3(s)⟶2NH3(g)+CO2(g)+H2O(g)(NH4)2CO3(s)⟶2NH3(g)+CO2(g)+H2O(g) Δ?gas=Δngas=   molmol H2(g)+Cl2(g)⟶2HCl(g)H2(g)+Cl2(g)⟶2HCl(g) Δ?gas=Δngas=   molmol 2H2(g)+O2(g)⟶2H2O(l)2H2(g)+O2(g)⟶2H2O(l) Δ?gas=Δngas=

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.100QE
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For each of the equations, determine the change in the number of moles of gas, Δ?gasΔngas.

(NH4)2CO3(s)⟶2NH3(g)+CO2(g)+H2O(g)(NH4)2CO3(s)⟶2NH3(g)+CO2(g)+H2O(g)

Δ?gas=Δngas=
 
molmol
H2(g)+Cl2(g)⟶2HCl(g)H2(g)+Cl2(g)⟶2HCl(g)
Δ?gas=Δngas=
 
molmol
2H2(g)+O2(g)⟶2H2O(l)2H2(g)+O2(g)⟶2H2O(l)
Δ?gas=Δngas=
 
molmol
2Na(s)+Cl2(g)⟶2NaCl(s)2Na(s)+Cl2(g)⟶2NaCl(s)
Δ?gas=Δngas=
 
mol
Expert Solution
Step 1

(NH4)2CO3(s)⟶2NH3(g)+CO2(g)+H2O(g)

Δn gas = 4-0 = 4 

H2(g)+Cl2(g)⟶2HCl(g)+H2(g)+Cl2(g)⟶2HCl(g)

Δn gas = 2-2 =0

2H2(g)+O2(g)⟶2H2O(l)2H2(g)+O2(g)⟶2H2O(l)
Δn gas= 0-3 = -3
 
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