# For many years drinking water has been cooled in hot climates by evaporating it from the surfaces of canvas bags or porous clay pots. How many grams of water can be cooled from 39.7 oC to 10oC by the evaporation of 80.4 g of water? (The heat of vaporization of water in this temperature range is 2.4 kJ/g. The specific heat of water is 4.18 J/(g∙K))

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For many years drinking water has been cooled in hot climates by evaporating it from the surfaces of canvas bags or porous clay pots. How many grams of water can be cooled from 39.7 oC to 10oC by the evaporation of 80.4 g of water? (The heat of vaporization of water in this temperature range is 2.4 kJ/g. The specific heat of water is 4.18 J/(g∙K))

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Step 1

The heat released (q) in the evaporation of the given amount of water can be calculated by multiplying the mass of water (mvap) undergoes evaporation with the heat of vaporization of water (ΔHvap).

Step 2

The mass of water (m) that can be cooled by the absorption of this amount of heat is calculated by using the equation (1). In this equation, s represents the spe...

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