For several years researchers have noticed that there appears to be a regular, year-by-year increase in the average IQ for the general population. This phenom- enon is called the Flynn effect after the researcher 00) and it
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- Marine biologists have noticed that the color of the outermost growth band on a clam tends to be related to the time of year in which the clam dies. A biologist conducted a small investigation of whether this is true for the species Protothaca staminea. She collected a sample of 50 clam shells in February and 27 clam shells in March. 15 of the shells from February had a dark color on the outermost growth band, whereas 8 of the shells from March had a dark color on the outermost growth band. Carry out a hypothesis test to see if there is a difference in the proportion of shells with a dark outermost growth band between the two months. The point estimate for the true difference in proportion of dark growth bands between February and March is:Marine biologists have noticed that the color of the outermost growth band on a clam tends to be related to the time of year in which the clam dies. A biologist conducted a small investigation of whether this is true for the species Protothaca staminea. She collected a sample of 50 clam shells in February and 27 clam shells in March. 15 of the shells from February had a dark color on the outermost growth band, whereas 8 of the shells from March had a dark color on the outermost growth band. Carry out a hypothesis test to see if there is a difference in the proportion of shells with a dark outermost growth band between the two months. Let ? = 0.01. A) The point estimate for the true difference in proportion of dark growth bands between February and March is:Marine biologists have noticed that the color of the outermost growth band on a clam tends to be related to the time of year in which the clam dies. A biologist conducted a small investigation of whether this is true for the species Protothaca staminea. She collected a sample of 50 clam shells in February and 27 clam shells in March. 15 of the shells from February had a dark color on the outermost growth band, whereas 8 of the shells from March had a dark color on the outermost growth band. Carry out a hypothesis test to see if there is a difference in the proportion of shells with a dark outermost growth band between the two months. Let ? = 0.01.Note: Do all calculations as February - March A) The point estimate for the true difference in proportion of dark growth bands between February and March is: I need help and webassign rejected the 0.0037 as the answer. I'm so lost. I emailed my professor and he hasn't gotten back to me. Please help. Thank you.
- Marine biologists have noticed that the color of the outermost growth band on a clam tends to be related to the time of year in which the clam dies. A biologist conducted a small investigation of whether this is true for the species Protothaca staminea. She collected a sample of 55 clam shells in February and 55 clam shells in March. 14 of the shells from February had a dark color on the outermost growth band, whereas 8 of the shells from March had a dark color on the outermost growth band. Carry out a hypothesis test to see if there is a difference in the proportion of shells with a dark outermost growth band between the two months; specifically, if the population proportion in February is higher than March. Let ? = 0.1.Note: Do all calculations as February - MarchA) The point estimate for the true difference in proportion of dark growth bands between February and March is: Note: answer using 4 decimal precisionB) The test statistic, ztest, is: Note: answer using 2 decimal…If you tested the same group of subjects under two different experimental conditions and accidentally used the t-test for independent groups in testing what would be the effect in the t-value computed?Laureysens, et al. (2004) studied the concentration of aluminum in wood from a number of clones of poplar growing in an area with heavy pollution. The same clone was sampled and tested once in August and again in November. The researchers believed that the concentration of aluminum would be shown to be increasing over time and hence higher in November than in August. The following table gives the aluminum concentrations for twelve of the clones. Clone 1 2 3 4 5 6 7 8 9 10 11 12 Aug. 8.1 10.0 16.5 13.6 9.5 8.3 18.3 13.3 7.9 8.1 8.9 13.4 Nov. 11.2 16.3 15.3 15.6 10.5 15.5 12.7 11.1 19.9 20.4 14.2 36.8 Diff. 3.1 6.3 1.2 2.0 1.0 7.2 5.6 2.2 12.0 12.3 5.3 23.4 The data are to be analyzed using the Wilcoxon signed rank test. H0: Values of aluminum concentrations in the 2 months have the same distribution. Ha: Values of aluminum concentrations are systematically larger in November than in August. Fix α = 0.05 What is the observed value of the statistic W+ used for the test of hypotheses?…
- The cuttlefish, a cephalopod and first cousin of the octopus, has the ability to camouflage to almost any natural sea environment instantaneously (within a few milliseconds). They are also able to camouflage to non-natural environments but not quite as quickly. A cognitive psychologist is interested in whether cuttles exhibit learning (by showing a reduction in reaction time) after repeated exposure to the same environment. Initially, 10 baby cuttlefish are individually placed in a tank with a checkerboard bottom and their reaction time (time to camouflage) is recorded. Over the next month the samecuttlefish are exposed to the same environment daily and at the end of the month each cuttlefish's reaction time is recorded again. The data are recorded in the table below. Reaction Time (seconds) Subject Before After 1 58 41 2 48 45 3 54 40 4 56 42 5 55 48 6 55 41 7 43 32 8 51 44 9 62 38 10 35…15. For several years researchers have noticed that thereappears to be a regular, year-by-year increase in theaverage IQ for the general population. Thisphenomenon is called the Flynn effect after theresearcher who first reported it (Flynn, 1984, 1999),and it means that psychologists must continuouslyupdate IQ tests to keep the population mean at 100. To evaluate the size of the effect, aresearcher obtained a 10-year-old IQ test that wasstandardized to produce a mean IQ of 100 for thepopulation 10 years ago. The test was then given to asample of n 64 of today’s 20-year-old adults. Theaverage score for the sample was M 107 with astandard deviation of s 12.a. Based on the sample, is the average IQ for today’spopulation significantly different from the average10 years ago, when the test would have producesa mean of 100? Use a two-tailed test with.01.b. Make an 80% confidence interval estimate oftoday’s population mean IQ for the 10-year-old test.An agricultural scientist tests six types of fertilizer, labeled A, B, C, D, E, and F, to determine whether any of them produces an increase in the yield of lima beans over that obtained with the current fertilizer. For fertilizer C, the increase in yield is statistically significant at the 0.05 level. For the other five, the increase is not statistically significant. The scientist concludes that the yield obtained with fertilizer C is greater than that of the current fertilizer. Explain why this conclusion is not justified.
- A large research project showed that in a sample of 750 adults, 60 of them experienced a midlife crisis . Use this data to test the claim that the percentage of adults who experienced midlife crisis is less than 10%. Use (alpha)= 0.05 .A study to compare two insurance companies on length of stay for pediatric asthma patients randomly sampled 393 cases from Insurer A. An independent random sample of 396 cases from Insurer B gave the results on length of stay, and the summary statistics are show below. Insurer A (Group 1): x⎯⎯⎯x¯ = 2.31, ss = 1.22, nn = 393Insurer B (Group 2): x⎯⎯⎯x¯ = 2.96, ss = 1.5, nn = 396 Unless otherwise stated, give your answers to three decimal places. Construct a 99% confidence interval for the difference in average length of stay between Insurer A and Insurer B. Give your answers to three decimal places. Use t∗=2.582t∗=2.582.( , ) Conduct a hypothesis test to determine whether the average length of stay for Insurer A is different from than the average length of stay for Insurer B. What is the parameter of interest?i. ppii. μμiii. p1−p2p1−p2iv. μ1−μ2μ1−μ2v. μdμd What is the correct null value for this test? What sign should appear in the alternative hypothesis?i. == ii.…A survey of 90 recently delivered women on the rolls of a county welfare department revealed that 27 had a history of intrapartum or postpartum infection. Can we conclude that the population proportion with a history of intrapartum or postpartum infection is significantly less than or equal to 0.25? Let alpha = 0.05.