For the circuit shown below, E = 26 V, L = 4.8 mH, and R = 4.5 N. After steady state is reached with S, closed and S, open,S2 is closed and immediately thereafter (at t = 0) S1 is opened.RS2R(a) Determine the current through L (in A) at t = 0.5.78A(b) Determine the current through L (in A) at t = 4.0 x 10-4 s.2.787× A(c) Determine the voltages across L and R (in V) at t = 4.0 x 10-4 s.VL10.98VR10.98|× v0000

Given ∈=26 VL = 4.8 mHR = 4.5 Ω

For the circuit shown below, E = 26 V, L = 4.8 mH, and R = 4.5 Q. After steady state is reached with S̟ closed and S2 open, Są is closed and immediately thereafter (at t = 0) s, is opened. R S2 E' .R (a) Determine the current through L (in A) at t = 0. 5.78 A (b) Determine the current through L (in A) at t = 4.0 x 10-4 s. 2.787 × A (c) Determine the voltages across L and R (in V) at t = 4.0 x 10-4 s. V = |10.98 VR = 10.98

For the circuit shown below, E = 26 V, L = 4.8 mH, and R = 4.5 Q. After steady state is reached with S̟ closed and S2 open, Są is closed and immediately thereafter (at t = 0) s, is opened. R S2 E' .R (a) Determine the current through L (in A) at t = 0. 5.78 A (b) Determine the current through L (in A) at t = 4.0 x 10-4 s. 2.787 × A (c) Determine the voltages across L and R (in V) at t = 4.0 x 10-4 s. V = |10.98 VR = 10.98

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter14: Inductance

Section: Chapter Questions

Problem 53P: For the circuit shown below, =20V , L = 4.0 mH, and R = 5.0 . After steady state is reached with S1...

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