Alert dont submit AI generated answer. For the following code, show the progress of the instructions using Tomasulo'sAlgorithm by providing information for following 3 tables until all write resultsare complete (i.e. show these 3 tables for each clock cycle with the correctcontents). The 3 tables for Clock Cycle 0 (initial condition) are provided below. Assumefld takes 2 CC, fadd.d takes 3 CC, and fsd takes 1 CC. Also assume that when any datais written to reservation stations or registers, that data cannot be accessed on the sameclock cycle.fld f0, 0(so)fadd.d f2, fo, fofsd f2, 0(s0)Clock Cycle 0 (initial)Table 1Instructionsfld f0, 0(s0)fadd.d f2, f0, fofsd f2, 0(s0)Table 2Instruction status1) Issue2) Execute3) Write resultsReservation stationsBusyOpVjVkQjQkANameLoadlLoad2StorelStore2AddlAdd2MultlMult2NZZ ZZZZZ ZNNNTable 3Register statusFieldfűf2 f4f6 f8f10f12Qi

Fulfilling the Floating-Point Arithmetic with Tomasulo's AlgorithmThis breakdown showcases the…

Answered: For the following code, show the…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Find the base and limit register value for each job in the memory when the order of the job going into the memory is Job 2, Job 4, Job 1, Job 3.Also tell what will happen if CPU request for the base address 306460 and limit address480215. please consider this image for solving the problem
In the below cases, comment on the situation about what type of instructions won’t work correctly if that failure happen. According at the figure that provided.Give the comments and example of instructions which still can be perform correctly under failure. a)RegWrite = 0 b)RegDst = 0c)PCSrc = 0
What is the execution result for each of the following instructions : - 1. LHLD 3003 ( [3OO2]=9OH,[30O4]=99H , [3OO1]=1OH,[3OO3]=43H)2.CMA ( If A= 9H ) 3. ADI A, 15H ( A=O1H) 4. INB (If B=34 H) 5. LXI * H 50 H
What would happen if an instruction was disobeyed, and why would that be the case? In the following scenarios, a TLB that is maintained by software is more efficient than one that is handled by hardware:
Given a memory load instruction, "mov R0; [R1+1000]," please give the input that should be selectedat each multiplexer. You can write "none" for the multiplexers that are not used for this instruction.(a) MUX1:(b) MUX2:(c) MUX3:(d) MUX4:
Enter the decimal equivalent to output "res" value in the following Verilog code after three rising edge of the clock with dir = 1, followed by two rising edge of the clock with dir = 0. module TesQ (clk, dir, res);input wire clk, dir;output reg [7:0] res ;integer i; initial begin res = 8'b10000; end always @ (posedge clk) begin if (dir) begin res = res + 8'b101; end else begin res = res - 8'b11; end endendmodule
I am still getting the same wrong output using the updated code that you provided. I moved the andi instruction after the srl instruction. This is the code that you provided with the fix: .data .globl main .textmain: # compute the next state of the LFSR for each input state li $a0, 0x00000001 jal lfsr_next_state move $t0, $v0 li $a0, 0xdeadbeef jal lfsr_next_state move $t1, $v0 li $a0, 0x200214c8 jal lfsr_next_state move $t2, $v0 li $a0, 0x00000000 jal lfsr_next_state move $t3, $v0 # print the output states li $v0, 1 move $a0, $t0 syscall li $v0, 1 move $a0, $t1 syscall li $v0, 1 move $a0, $t2 syscall li $v0, 1 move $a0, $t3 syscall # exit the program li $v0, 10 syscall # Function to compute the next state of an LFSR# Input parameter: $a0 = current state# Output:…
Using the Figure 4.11 in the text (also shown in slide 26 of lecture on Feb 24th, and below), trace the execution of the instructions for the next TWO cycles, by indicating what are the values on the busses (wires), or registers that correspond to the following entries in the table: For clarity, please show your answer in Hexadecimal system the way the PC value is shown for the 'Current Clock Cycle' in the table If an entry is a 'don't care' for that cycle you have to indicate it as "DONT CARE", as shown below also Net/Register/Control Current Clock Cycle (Show in Hex) Next Clock Cycle (Show in Hex) Contents of PC 0X00000014 Read Register 1 value (input) Read Register 2 value (input) Write Register value (input) Write Data value of 'Registers' block (input) Read data 1 (output) Read data 2 (output) Input to the Sign-extend (16 bit value) DONT CARE Output of the Sign-extend (32 bit value) Address input to the Data Memory…
Explain what happens as the following sequences of instructions are executed : Again: MOV DL,05H MOV AX,0A00H MOV DS ,AX MOV SI,0H MOV CX,0FH INC SI CMP [SI],DL LOCPNE Again
Question 7: In the following instruction sequence, show the resulting value of AL where indicated, in Hexadecimal: a. mov al,7Ah not al ; . b. mov al,72h xor al,0DCh ; and also write instructions that first clear bit positions 0,1 and 2 in AL. Then, if the destination operand is equal to zero, the code should jump to label LABEL1. Otherwise, it should jump to label NEXT
What would occur if an instruction were to be disregarded? A software-managed TLB is quicker than a hardware-managed TLB in the following situations:
Evaluate the following postfix expression and write down the corresponding instructions for a 0-address machine.5 4 + 9 3 / -

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