For the following figure, the mass of the box is 32 kg the stiffness of the spring is 500 N/m and the radius r=18 cm (Hint: Jo-10)The Kinetic energy will be in the form ofQ0²T =The Potential energy will be in the form ofU=P 0²After Applying the Energy method to calculate the equation of motion, the form of the equation of the motion will be as:A + BO=0OA mThe constant Qis: Choose..The constant A isThe constant B is:The constant P isChoose.Choose.Choose4rX(t)Ok

Answered: Image /qna-images/answer/7296b043-2490-4716-b714-9589a6397ed5.jpg

For the following figure, the m The Kinetic energy will be in the form of T = Q8² The Potential energy will be in the form of U-P0² kg the stiffness of the After Applying the Energy method to calculate the equation of motion, the form the form of the equation of the motion will be as AB + Be=0

For the following figure, the m The Kinetic energy will be in the form of T = Q8² The Potential energy will be in the form of U-P0² kg the stiffness of the After Applying the Energy method to calculate the equation of motion, the form the form of the equation of the motion will be as AB + Be=0

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter1: Tension, Compression, And Shear

Section: Chapter Questions

Problem 1.3.18P: A stepped shaft ABC consisting of two solid, circular segments is subjected to uniformly distributed...

See similar textbooks

Similar questions

A stepped shaft ABC consisting of two solid, circular segments is subjected to uniformly distributed torque t1acting aver segment 1 and concentrated torque t2applied at C, as shown in the figure. Segment 1 of the shaft has a diameter of d1= 57 mm and length of L1= 0.75 m; segment 2 has a diameter d2— 44 mm and length L2= 0.5 m. Torque intensity /,"= 3100 N . m/m and T2= 1100 N. m. (a) Find reaction torque TAat support A. (b) Find the internal torque T(x) at two locations: .x = L1/2 and at .x = L1+ L2/2. Show these internal torques on properly drawn free-body diagrams.
For the double slider mechanism shown in the following figure, the crank OA rotates at a uniform speed of 100 rad/s CW. we need to find the required torque for the crank, if two forces act at sliders B and C as shown in the figure. (P = 2KN, Q = 1KN). OA = 30 cm, AB = AC = 100 cm. mB = mC = 1 Kg. Neglect other links weights. The velocity of slip of slider B in m/s2 = Answer 1 Choose... The velocity of slip of slider C in m/s2 = Answer 2 Choose... The acceleration of slip of slider B in m/s2 = Answer 3 Choose... The acceleration of slip of slider C in m/s2 = Answer 4 Choose... The magnitude of required torque for the crank in N.m = Answer 5 Choose...
Under some circumstances, when two parallel springswith constants k1 and k2 support a single mass, theeffective spring constant of the system is given byk 4k1k2/(k1 + k2). A mass weighing 20 pounds stretchesone spring 6 inches and another spring 2 inches. Thesprings are first attached to a common rigid supportand then to a metal plate. As the figure illustrates(see image), the mass is attached to the center of the plate in the distributiondouble spring. Determine the constant of theeffective spring for this system. find the equationof motion if the mass is initially released fromequilibrium position with downward speed of2 ft/sec.
Problem A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. Solution a) Let us first derive the expression for the tension. By Newton's First Law ΣF = ______ the components of force that makes this so is ΣF = T ______-______ = 0 Simplifying this results to T = _____g/_____(ϕ) Analyzing the figure above, we arrive at _____(ϕ) = sqrt( _____2 +_____ ) / ( _____/_____ +_____ ) By substitution, we arrive at the following: T = _____( _____ + 2_____ ) g / ( _____ sqrt ( _____2 +_____ ) ) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T = __________0.370 N
For the double slider mechanism shown in the following figure, the crank OA rotates at a uniform speed of 24 rad/s ccw. we need to find the required torque for the crank, if two forces act at sliders B and C as shown in the figure. (P = 4 kN, Q = 2 kN). OA = 10 cm, AB = AC = 70 cm. mg = mc = 5 Kg. Neglect other links weights. (5) (2) (3) B (4) (6) C 45° X. The velocity of slip of slider B in m/s² = Choose.. + The velocity of slip of slider C in m/s? = Choose... + The acceleration of slip of slider B in m/s² = Choose.. + The acceleration of slip of slider C in m/s² = Choose.. + The magnitude of required torque for the crank in N.m = Choose..
In the given fig shows the suspension system of a freight truck with a parallel-spring arrangement. Find the equivalent spring constant of the suspension if each of the three helical springs is made of steel with a shear modulus G = 120GPaand has five effective turns, mean coil diameter D = 50 cm, and wire diameter d = 5 cm
A 27‑kg sing is attached to the right end of a horizontal beam (the beam's mass m = 7.7 kg). The left end of the beam is mounted into a wall and it's right end is supported by a string which makes an angle θ = 32° with the beam, see the picture below. Find the magnitude of the tension in the string. 1. The tension in the string, T Find the reaction force exerted by the wall on the beam. 2. The x component of the wall's reaction force, Rx = 3. The y component of the wall's reaction force, Ry =
A mono-cylinder engine has r = 0.3 m, l = 0.9 m, It has: crank mass m2 = 4.5 kg , crank rG2 = 0.4r, conrod mass m3 = 12 kg ,conrod rG3 = 0.3l from A, and piston m4 = 5 kg. The crank is rotating at constant speed ω =3000 rpm. The following equation is an approximation of the gas force over 180° of crank angle with Fgmax = 3000 N and β = 15º. we need to find the gas force, gas torque, and inertia force . Use approximate expressions in your calculation
MECHANICAL VIBRATIONS USE VIRTUAL WORK HOW DID IT REACH TO THIS ANSWER? THIS IS ACCORDING TO THE ANSWER KEY OF THE BOOK The uniform bar shown in Fig. P3.6 has mass m, length l, and mass momentof inertia I about its mass center. The bar is supported by two springs k1and k2, as shown in the figure. Obtain the differential equation of motion anddetermine the natural frequency of the system in the case of small oscillations.
1-) length L with mass m given in the figure on the sidemass M is connected to the end of the rod and has a coefficient of kit is connected with the spring on a fixed bearing. a-) giving the natural frequency of the system for the state in the figureget the statement. B-increase of spring coefficient like 0.5 k, 2k, 5k and / orhow does the natural frequency of the system decreasereferencesexternal links
Example: A (1.84 N) body is suspended by a spring which is stretched (15.3 cm) when it is loaded. If the body is drawn down (10 ¢m) from the position of equilibrium; find the position of the spring as a function of time (7) if: . €=15 2. ¢=3.75 3.¢=3 Dashpot | E=
See the attached image1) A long rod in the shape of a circular cone is rotating with constant angular velocity c about an axis located at the left end of the rod as shown in the figure below. The bar has length L, major and minor diameters D and d, respectively, and its material has linear elastic behavior with modulus of elasticity E. The values of the problem parameters must be defined by the student a) From the balance of a differential member of the bar, derive the differential equation of balance for the bar. Solve the equation analytically to obtain the bar displacement field, U(X). Give the expression for the displacement at the free end of the member. b) Implement a computational code in MATLAB (or any other software) to solve this problem with "n" two-node bar finite elements. c) Run different simulations by increasing the number of finite elements in each simulation. At each simulation, obtain the displacement of the free end of the member. Graphically compare your results…