For the following synopsis, fill in your answers in the Punnett Square drawn below for each of the two F2 purple seedlings. Suppose that instead of being ground up, your seedling had been allowed to grow into a plant and then be cross-pollinated with a plant with the genotype ANL/gnl, F2 purple #1 allele 1 result goes here allele 2 result goes here ANL Anl F2 purple #2| allele 1 result goes here | allele 2 result goes here ANL Anl,
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data for the question
- A homozygous purple plant will have a single PCR product band
- CF and PR primers: 899 bps
- A heterozygous purple plant will have two PCR product bands
- CF and PR primers: 899 & 1279 bps
- A homozygous green plant will have a single PCR product band
- CF and PR primers: 1279 bps
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- A researcher crosses two white-flowered lines ofAntirrhinum plants as follows and obtains the followingresults:pure line 1 × pure line 2↓F1 all whiteF1 × F1↓F2 131 white29 reda. Deduce the inheritance of these phenotypes; useclearly defined gene symbols. Give the genotypes ofthe parents, F1, and F2.b. Predict the outcome of crosses of the F1 with eachparental line.A snapdragon with pink petals, black anthers, and longstems was allowed to self-fertilize. From the resultingseeds, 650 adult plants were obtained. The phenotypesof these offspring are listed here.78 red long tan26 red short tan44 red long black15 red short black39 pink long tan13 pink short tan204 pink long black68 pink short black5 white long tan2 white short tan117 white long black39 white short blacka. Using P for one allele and p for the other, indicatehow flower color is inherited.b. What numbers of red : pink : white would havebeen expected among these 650 plants?c. How are anther color and stem length inherited?d. What was the genotype of the original plant?e. Do any of the three genes show independentassortment?f. For any genes that are linked, indicate the arrangements of the alleles on the homologous chromosomes in the original snapdragon, and estimate thedistance between the genesA researcher studied six independently assorting genes in a plant. Each gene has a dominant and a recessive allele: R black stem, r red stem; D tall plant, d dwarf plant; C full pods, c constricted pods; O round fruit, o oval fruit; H hairless leaves, h hairy leaves; W purple flower, w white flower From the cross (P1) RrDdccOoHhWw x (P2) RrddCcooHhww, determine: Note: RrDdccOoHhWw is one genotype. a. How many kinds of gametes can be formed by P1?b. How many genotypes are possible among the progeny of this cross?c. How many phenotypes are possible among the progeny?d. What is the probability of obtaining the RrDdccOohhww genotype in the progeny?e. What is the probability of obtaining a black, dwarf, constricted, oval, hairy, purple phenotype in the progeny?
- In corn, a triple heterozygote was obtained carrying themutant alleles s (shrunken), w (white aleurone), andy (waxy endosperm), all paired with their normal wildtype alleles. This triple heterozygote was testcrossed, andthe progeny contained 116 shrunken, white; 4 fully wildtype; 2538 shrunken; 601 shrunken, waxy; 626 white;2708 white, waxy; 2 shrunken, white, waxy; and 113 waxy.a. Determine if any of these three loci are linked and,if so, show map distances.b. Show the allele arrangement on the chromosomesof the triple heterozygote used in the testcross.c. Calculate interference, if appropriate.Given the following pathway on the image: G and H are dominant alleles of the two independently assorting genes that produce an enzyme that catalyzes the conversion of one pigment to another, and g and h are recessive alleles that are non-functional. A true-breeding blue plant is crossed with a white plant of genotype ggHH. The F1s are allowed to self-mate. 1. What proportions would you expect in the F2 progeny? 2. Which is the epistatic allele?. In nature, the plant Plectritis congesta is dimorphic forfruit shape; that is, individual plants bear either winglessor winged fruits, as shown in the illustration.Wingless fruit Winged fruitPlants were collected from nature before floweringand were crossed or selfed with the following results:Number of progenyPollination Winged WinglessWinged (selfed) 91 1*Winged (selfed) 90 30Wingless (selfed) 4* 80Winged × wingless 161 0Winged × wingless 29 31Winged × wingless 46 0Winged × winged 44 0*Phenotype probably has a nongenetic explanation.Interpret these results, and derive the mode ofinheritance of these fruit-shaped phenotypes. Usesymbols. What do you think is the nongeneticexplanation for the phenotypes marked by asterisks inthe table?
- In corn plants, two pairs of genes control color in the ears of corn. The following genotypes result in various colors: W-C- [red]; wwC- [yellow]; W-cc [white]; wwcc [white]. What is the phenotypic ratio of the dihybrid cross between corn plants heterozygous for both genes? (Dashes mean the allele could be W or w, i.e., WWCC/WwCC/WWCc/WwCc geneotype gives red color)Mendelian GeneticsF1 Cross: Yellow, Round x Green, RoundGgWw x ggWWCharacter: Pea color & shapeUse Punnett square and fork-line method to check the F2.Show and interpret all the possible genotypes and phenotypes of the offsprings.Mendelian GeneticsF1 Cross: Tall, White, Axial x Dwarf, Violet, TerminalDdwwAA x ddWWaaCharacter: Stem height, Flower color & positionUse fork-line method to check the F2.Show and interpret all the possible genotypes and phenotypes of the offsprings.B.A.I. For A and B,1. Identify the type ofinheritance. Justifyyour answer.2. Decode the genotypesof the individuals inthe pedigree. (Useletter A forrepresentation ofalleles.)3. List down all affected. In the tiny model plant Arabidopsis, the recessive allele hyg confers seed resistance to the drug hygromycin, and her, a recessive allele of a different gene, confers seed resistance to herbicide. A plant that was homozygous hyg/hyg ⋅ her/her was crossed with wild type, and the F1 was selfed. Seeds resulting from the F1 self were placed on petri dishes containing hygromycin and herbicide.a. If the two genes are unlinked, what percentage of seeds are expected to grow?b. In fact, 13 percent of the seeds grew. Does this percentage support the hypothesis of no linkage? Explain. If not, calculate the number of map units between the loci.c. Under your hypothesis, if the F1 is testcrossed, what proportion of seeds will grow on the medium containing hygromycin and herbicide?
- Two true breeding plants are cross pollinated. One plant is homozygous dominant for heightand color while the other is homozygous recessive for height and color. (A:tall, a:short, B:brown,b:red) The F1 plants are allowed to self-fertilize to produce an F2 generation. After conductingan experiment we get the following results:398 tall and brown plants122 tall and red plants128 short and brown plants45 short and red plants Using the Chi Square formula and table, determine if your results support the hypothesis ofindependent assortment or not. Show your work. You don’t need to show your Punnett Squaresif you include a statement as to how you figured out the appropriate phenotypic ratio for the F2generation. Round to 1 decimal.4a. What possible gametes can the following individual make: AaBb4b. What possible gametes can the following individual make: AaBbCCMendelian GeneticsF1 Cross: Yellow, Round x Green, Round GgWw x ggWWCharacter: Pea color & shapeUse Punnett square and fork-line method to check the F2.Show and interpret all the possible genotypes and phenotypes of the offsprings. Mendelian GeneticsF1 Cross: Tall, White, Axial x Dwarf, Violet, Terminal DdwwAA x ddWWaaCharacter: Stem height, Flower color & positionUse fork-line method to check the F2.Show and interpret all the possible genotypes and phenotypes of the offsprings. I. For A and B,1. Identify the type of inheritance. Justify your answer.2. Decode the genotypes of the individuals in the pedigree. (Use letter A for representation of alleles.)3. List down all affected individuals.B.A.In 1911. Thomas Hunt Morgan collected the following crossover gene frequencieswhile studying Drosophila. Bar-shaped eyes are indicated by the B allele, andcarnation eyes are indicated by the allele C. Fused veins on wings (A) and scallopedwings (S) are located on the same chromosomes