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Draw a Punnett square for the dihybrid cross described below (it is the same story as given for question 8, above) and use it to fill in the blanks correctly in the text that follows. NOTE: Please type in whole numbers, no symbols. There are two known alleles of gene occupying a specific locus in the X chromosome. The gene in question codes for a transcription factor involved in digit development. The mutant allele is dominant and gives rise to an additional but non-functioning little finger (polydactyly) on both hands. A couple have had their DNA sequenced at the region of interest, the male exhibits polydactyly because of the mutation, the female is homozygous wild type at the same locus and therefore has the wild type phenotype. Both have green eyes. In this story; eye colour shows a monogenic autosomal inheritance pattern and the allele for brown eyes shows incomplete dominance with that for blue eyes, the heterozygote phenotype is green eyes. The genes for eye colour and polydactyly show no linkage. ANSWER: In the dihybrid cross described above Blank 1 percent of the female offspring are expected to be blue eyed. Blank 2 percent of the offspring are expected to show polydactyly as a result of inheriting the X linked mutation. The couple in the story above have eight children of which Blank 3 would be expected to have blue eyes. Blank 1 Add your answer Blank 2 Add your answer Blank 3 Add your answer

Draw a Punnett square for the dihybrid cross described below (it is the same story as given for question 8, above) and use it to fill in the blanks correctly in the text that follows. NOTE: Please type in whole numbers, no symbols. There are two known alleles of gene occupying a specific locus in the X chromosome. The gene in question codes for a transcription factor involved in digit development. The mutant allele is dominant and gives rise to an additional but non-functioning little finger (polydactyly) on both hands. A couple have had their DNA sequenced at the region of interest, the male exhibits polydactyly because of the mutation, the female is homozygous wild type at the same locus and therefore has the wild type phenotype. Both have green eyes. In this story; eye colour shows a monogenic autosomal inheritance pattern and the allele for brown eyes shows incomplete dominance with that for blue eyes, the heterozygote phenotype is green eyes. The genes for eye colour and polydactyly show no linkage. ANSWER: In the dihybrid cross described above Blank 1 percent of the female offspring are expected to be blue eyed. Blank 2 percent of the offspring are expected to show polydactyly as a result of inheriting the X linked mutation. The couple in the story above have eight children of which Blank 3 would be expected to have blue eyes. Blank 1 Add your answer Blank 2 Add your answer Blank 3 Add your answer

Human Heredity: Principles and Issues (MindTap Course List)
Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN:9781305251052
Author:Michael Cummings
Publisher:Michael Cummings
Chapter6: Cytogenetics: Karyotypes And Chromosome Aberrations
Section: Chapter Questions
Problem 2QP: Given the karyotype shown at right, is this a male or a female? Normal or abnormal? What would the...
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Draw a Punnett square for the dihybrid cross described below (it is the same story as given for question 8, above) and use it to fill in the blanks correctly in the text that follows. NOTE: Please type in whole numbers, no symbols. There are two known alleles of gene occupying a specific locus in the X chromosome. The gene in question codes for a transcription factor involved in digit development. The mutant allele is dominant and gives rise to an additional but non-functioning little finger (polydactyly) on both hands. A couple have had their DNA sequenced at the region of interest, the male exhibits polydactyly because of the mutation, the female is homozygous wild type at the same locus and therefore has the wild type phenotype. Both have green eyes. In this story; eye colour shows a monogenic autosomal inheritance pattern and the allele for brown eyes shows incomplete dominance with that for blue eyes, the heterozygote phenotype is green eyes. The genes for eye colour and polydactyly show no linkage. ANSWER: In the dihybrid cross described above Blank 1 percent of the female offspring are expected to be blue eyed. Blank 2 percent of the offspring are expected to show polydactyly as a result of inheriting the X linked mutation. The couple in the story above have eight children of which Blank 3 would be expected to have blue eyes. Blank 1 Add your answer Blank 2 Add your answer Blank 3 Add your answer
Transcribed Image Text:Draw a Punnett square for the dihybrid cross described below (it is the same story as given for question 8, above) and use it to fill in the blanks correctly in the text that follows. NOTE: Please type in whole numbers, no symbols. There are two known alleles of gene occupying a specific locus in the X chromosome. The gene in question codes for a transcription factor involved in digit development. The mutant allele is dominant and gives rise to an additional but non-functioning little finger (polydactyly) on both hands. A couple have had their DNA sequenced at the region of interest, the male exhibits polydactyly because of the mutation, the female is homozygous wild type at the same locus and therefore has the wild type phenotype. Both have green eyes. In this story; eye colour shows a monogenic autosomal inheritance pattern and the allele for brown eyes shows incomplete dominance with that for blue eyes, the heterozygote phenotype is green eyes. The genes for eye colour and polydactyly show no linkage. ANSWER: In the dihybrid cross described above Blank 1 percent of the female offspring are expected to be blue eyed. Blank 2 percent of the offspring are expected to show polydactyly as a result of inheriting the X linked mutation. The couple in the story above have eight children of which Blank 3 would be expected to have blue eyes. Blank 1 Add your answer Blank 2 Add your answer Blank 3 Add your answer
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