For the following three vectors, what is 3C · (2 A✕B )?  A= 2.00i + 3.00j − 7.00k  B= −3.00i + 7.00j + 2.00k  C= 3.00i − 8.00j

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter1: Introduction And Vectors
Section: Chapter Questions
Problem 47P
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For the following three vectors, what is 3C · (2 A✕B )?

 A= 2.00i + 3.00j − 7.00k
 B= −3.00i + 7.00j + 2.00k
 C= 3.00i − 8.00j
Expert Solution
Step 1

Given,

A=2i^+3j^-7k^B=-3i^+7j^+2k^C=3i^-8j^

So we have,

3C=33i^-8j^=9i^-24j^

and

2A=22i^+3j^-7k^=4i^+6j^-14k^

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