For the proposed mechanism of conversion of ozone into oxygen gas (20,(g)-30,(g)). The rate law will have the following form: * 03(9) E02(9) + 0) (slow) 03(g) k- 03(9) + Og) 2, 202(9) (fast) rate = 2k,k [O][o] rate = 2k[0] rate = k,k,[0,] rate = 2k,[0] rate = 2k,k[O] %3D

Chemistry by OpenStax (2015-05-04)
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ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
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Chapter12: Kinetics
Section: Chapter Questions
Problem 1E: What is the difference between average rate, initial rate, and instantaneous rate?
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physical chemistry
For the proposed mechanism of conversion of
ozone into oxygen gas (20,(g)→30,(g)). The rate
law will have the following form: *
k1
03(9) E
02(9) + 0(g) (slow)
k-1
03(g)
+ 0(g)
2, 202(9) (fast)
rate = 2k,k[0,][0]
rate = 2k [0]
rate = k,k[0]
rate = 2k [0]
rate = 2k,k[0]
Transcribed Image Text:For the proposed mechanism of conversion of ozone into oxygen gas (20,(g)→30,(g)). The rate law will have the following form: * k1 03(9) E 02(9) + 0(g) (slow) k-1 03(g) + 0(g) 2, 202(9) (fast) rate = 2k,k[0,][0] rate = 2k [0] rate = k,k[0] rate = 2k [0] rate = 2k,k[0]
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