Question
Asked Nov 13, 2019
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For the reaction
3
KCIO3 KCI
2
assign oxidation numbers to each element on each side of the equation.
K in KCIO3
K in KCl:
Cl in KCIO3
Cl in KCl:
O in O2
O in KCIO3
Which element is reduced?
Which element is oxidized?
Cl
Ок
Ок
OC
L
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For the reaction 3 KCIO3 KCI 2 assign oxidation numbers to each element on each side of the equation. K in KCIO3 K in KCl: Cl in KCIO3 Cl in KCl: O in O2 O in KCIO3 Which element is reduced? Which element is oxidized? Cl Ок Ок OC L

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Expert Answer

Step 1

Oxidation state of each element of in KClO3, ...

Oxidation state of each elements in KCIO;:
К
+1
>
O
- 2
Cl ?
1(+1)X3 0
Oxidation state of Cl
Oxidation state of each elements in KCl:
К
+1
Cl 1
Oxidation state of O in O, = 0
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Oxidation state of each elements in KCIO;: К +1 > O - 2 Cl ? 1(+1)X3 0 Oxidation state of Cl Oxidation state of each elements in KCl: К +1 Cl 1 Oxidation state of O in O, = 0

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