For the situation in the figure below, use momentum conservation to determine (a) the magnitude and (b) the direction of the finalvelocity of ball 1 after the collision. The angle = 42.0⁰.(a) Number01 = 0.900 m/sm₂ = 0.150 kg(b) Number i02=0.540 m/sm₂ = 0.260 kgUnits35.0(b)(a) Top view of two balls colliding on a horizontal surface.(b) This part of the drawing shows the x and y components of the velocity of ball 1 after the collision.Units197x2 = 0.700 m/s

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For the situation in the figure below, use momentum conservation to determine (a) the magnitude and (b) the direction of the final velocity of ball 1 after the collision. The angle = 42.0⁰. (a) Number (b) Number 01=0.900 m/s my= 0.150 kg 20.540 m/s my 0.260 kg Units 35.0 Units 1918 191 (a) Top view of two balls colliding on a horizontal surface. (b) This part of the drawing shows the x and y components of the velocity of ball 1 after the collision. =0.700 m/s

For the situation in the figure below, use momentum conservation to determine (a) the magnitude and (b) the direction of the final velocity of ball 1 after the collision. The angle = 42.0⁰. (a) Number (b) Number 01=0.900 m/s my= 0.150 kg 20.540 m/s my 0.260 kg Units 35.0 Units 1918 191 (a) Top view of two balls colliding on a horizontal surface. (b) This part of the drawing shows the x and y components of the velocity of ball 1 after the collision. =0.700 m/s

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter8: Linear Momentum And Collisions

Section: Chapter Questions

Problem 51PE: Starting with equations m1v1=m1v1cos1+m2v2cos2 and 0=m1v1cos1+m2v2sin2 for conservation of momentum...

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