I need solution for 4.2 and 4.3 44.14.24.3Newton's Laws of MotionTwo blocks rest on a horizontalfrictionless surface as shown. Thesurface between the top and bottomblocks is roughened so that there is noslipping between the two blocks. A 30N force is applied to the bottom blockas suggested in the figure.(b)(c)(d)What is the magnitude of the acceleration of the "two block" system?302m/s²5+10(b)(d)(e)(a)(b)(d)(e)a = F1 m/s²2 m/s²3 m/s²6 m/s²15 m/s²What is the magnitude of the force of static friction between the top and bottom blocks?zero newtons2x510 N20 N25 N30 N0.050.100.200.300.40Frehend=mqa5 kg10 kg↓1819.8What is the minimum coefficient of static friction necessary to keep the top block fromslipping on the bottom block?Fr= MN30 NNOVOTE

Given that: The mass of the blocks are m=5 kgm'=10 kgM=m+m'=15 kg The applied force isF=30 N. It…

What is the magnitude of the force of static friction between the top and bottom blocks? (a) zero newtons 2x5 ((b) 10 N 20 N 25 N 30 N What is the minimum coefficient of static friction necessary to keep the top block from slipping on the bottom block? Mos

What is the magnitude of the force of static friction between the top and bottom blocks? (a) zero newtons 2x5 ((b) 10 N 20 N 25 N 30 N What is the minimum coefficient of static friction necessary to keep the top block from slipping on the bottom block? Mos

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter5: The Laws Of Motion

Section: Chapter Questions

Problem 5.20CQ: Balancing carefully, three boys inch out onto a horizontal tree branch above a pond, each planning...

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Question

I need solution for 4.2 and 4.3

4
4.1
4.2
4.3
Newton's Laws of Motion
Two blocks rest on a horizontal
frictionless surface as shown. The
surface between the top and bottom
blocks is roughened so that there is no
slipping between the two blocks. A 30
N force is applied to the bottom block
as suggested in the figure.
(b)
(c)
(d)
What is the magnitude of the acceleration of the "two block" system?
30
2m/s²
5+10
(b)
(d)
(e)
(a)
(b)
(d)
(e)
a = F
1 m/s²
2 m/s²
3 m/s²
6 m/s²
15 m/s²
What is the magnitude of the force of static friction between the top and bottom blocks?
zero newtons
2x5
10 N
20 N
25 N
30 N
0.05
0.10
0.20
0.30
0.40
Frehend
=
mqa
5 kg
10 kg
↓
1819.8
What is the minimum coefficient of static friction necessary to keep the top block from
slipping on the bottom block?
Fr= MN
30 N
NOVOTE

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