For this question, is this an endothermic or exothermic reaction? I am confused at the part where work is negative and heat is positive, because I thought they were all either pos or neg. thank you.
For this question, is this an endothermic or exothermic reaction? I am confused at the part where work is negative and heat is positive, because I thought they were all either pos or neg. thank you.
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section: Chapter Questions
Problem 110SCQ: Peanuts and peanut oil are organic materials and bum in air. How many burning peanuts does it take...
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For this question, is this an endothermic or exothermic reaction? I am confused at the part where work is negative and heat is positive, because I thought they were all either pos or neg. thank you.
Transcribed Image Text:Cnarge inheat
sotemexpands
aheatadded
3. A balloon is inflated to its full extent by(heating, The volume of the balloon changes from
4.0x106 liters to 4.5x10° liters by the addition of 1.3x10 Joules of energy as heat. Calculate
the change in internal energy, AE, for the process (assume the balloon expands at constant
pressure of 1.00 atm). {Hint: R = 0.08206 L·atm/mole-K = 8.3145 J/mole K}
gasconstant
Change inheak
gasconstant
%3D
%3D
for youles
AE = q + w = heat + work
Because heat is added, the internal energy of the system increases and q = +1.3x10 J
%3D
The system expands and does work on the surroundings, so work is a negative quantity
finas
w = -PAV = -(1.00 atm)(4.5x10ʻ L – 4.0x10° L)E-5.0x10° L·atm
initigl change in volume
%3D
We must convert this value to Joules before we can subtract it from 1.3x10% J
Dividing the two values of the Gas Constant R gives us:
work = (-P)(AV)
%3D
8.3145 J/mole K/0.08206 L'atm/mole K= 101.322 J/L'atm
w = (-5.0x10 L'atm)(101.322 J/L•atm) = -5.07x107 J
%3D
%3D
AE = 1.3x108 J – 5.07x107 J = 7.93x107 J
%3D
8.31453/mate V
b
= 101.323/om
O.08206L•am
/mble h
-5.0x10°-atm
101.322y
-5.07x10
%3D
1
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