Four computers are sending the digital data over a multiplexed line as shown in the Figure below. A). Show how the messages are multiplexed into frames using synchronous TDM and Asynchronous TDM. B). How many frames are generated if you are using Synchronous TDM?

Four computers are sending the digital data over a multiplexed line as shown in the Figure below. A). Show how the messages are multiplexed into frames using synchronous TDM and Asynchronous TDM. B). How many frames are generated if you are using Synchronous TDM?

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter8: Data And Network Communication Technology

Section: Chapter Questions

Problem 4VE

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Concept explainers

Transmission media

A communication channel that transmits data from a source to a recipient is referred to as "transmission media." Electromagnetic impulses are used to transmit data. Transmission media's primary purpose is to transmit data in the form of bits via a local area network (LAN). In data transport, it is the physical link that connects the transmitter and receiver. Transmission medium is part of layer 1 or physical layer of the ISO/OSI (Open System Interconnection) model.

Question

Four computers are sending the digital data over a
multiplexed line as shown in the Figure below.
A). Show how the messages are multiplexed into
frames using synchronous TDM and Asynchronous
TDM.
B). How many frames are generated if you are using
Synchronous TDM?
С.) How
asynchronous TDM with frame size 3?
many
frames are generated if you are using
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Four computers are sending the digital data over a multiplexed line as shown in the Figure below. A). Show how the messages are multiplexed into frames using synchronous TDM and Asynchronous TDM. B). How many frames are generated if you are using Synchronous TDM? C.) How many frames are generated if you are using asynchronous TDM with frame size 3?
Dear Writer this is my calculation solution.could you please double check it and let me know it if it soccrect or should i proceed with your solution: Please provide justification if correction is need and correct answer.Thank you in advance. a) The transmission time of a frame can be calculated as follows: Propagation delay (Tp) = distance/speed = 5km / 200000 km/s = 0.0025ms Transmission time (Tt) = frame size/bandwidth = 10000 * 8bits / (1Mbps * 10 ^ 6) = 0.008sec = 8ms Total time for transmission = 2 * Tp + Tt(since the frame has to travel from A to D and then D to A) = 2 * 0.0025ms + 8ms = 0.005ms + 8ms = 8.005ms The transmission time of the frame from A to D is 8.005 ms. b) The efficiency of the CSMA/CD protocol is given by the formula: Tt is the transmission time of a frame C is the number of collisions, Tp is the propagation time of a signal from one end of the segment to the other. Efficiency = Tt / (C * 2 * Tp + Tt + Tp) Assuming that there are no other…
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This is my solution, Please check the solution and let me know If my solution is correct:Please adjust your decisiona nd provide corrected version if it is needed. a) The transmission time of a frame can be calculated as follows: Propagation delay (Tp) = distance/speed = 5km / 200000 km/s = 0.0025ms Transmission time (Tt) = frame size/bandwidth = 10000 * 8bits / (1Mbps * 10 ^ 6) = 0.008sec = 8ms Total time for transmission = 2 * Tp + Tt(since the frame has to travel from A to D and then D to A) = 2 * 0.0025ms + 8ms = 0.005ms + 8ms = 8.005ms The transmission time of the frame from A to D is 8.005 ms. b) The efficiency of the CSMA/CD protocol is given by the formula: Tt is the transmission time of a frame C is the number of collisions, Tp is the propagation time of a signal from one end of the segment to the other. Efficiency = Tt / (C * 2 * Tp + Tt + Tp) Assuming that there are no other stations transmitting or attempting to transmit on the segment, the transmission from…
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